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2.4: Zeros of Polynomial Functions

2.4: Zeros of Polynomial Functions

Assessment

Presentation

β€’

Mathematics

β€’

12th Grade

β€’

Medium

Created by

Noor Shamlan

Used 3+ times

FREE Resource

6 Slides β€’ 8 Questions

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3

Multiple Choice

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List all possible rational zeros of f(x). Then determine which are zeros.?

1

x=1Β ,Β x=Β 7x=1\ ,\ x=\ \sqrt[]{7}  

2

x=1x=1  

3

x=1Β ,Β x=Β 7,Β x=βˆ’Β 7x=1\ ,\ x=\ \sqrt[]{7},\ x=-\ \sqrt[]{7}  

4

Multiple Choice

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List all possible rational zeros of f(x). Then determine which are zeros.?

1

x=2Β ,Β x=βˆ“3𝑖x=2\ ,\ x=βˆ“3𝑖  

2

x=2x=2  

3

x=βˆ“3𝑖x=βˆ“3𝑖  

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6

Multiple Choice

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1

πŸ”Β andΒ βˆ’12.πŸ”\ and\ \frac{-1}{2}.  

2

Β Β βˆ’12\ \ \frac{-1}{2}  

3

66  

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Multiple Choice

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1

h(x) has 3 variation in sign, h(x) has 3 positive real zeros.h(-x) has 1 variations in sign, h(x) has 1 negative real zero.

2

h(x) has 2 variation in sign, h(x) has 2 positive real zeros.h(-x) has 1 variations in sign, h(x) has 1 negative real zero.

3

h(x) has 4 variation in sign, h(x) has 4 positive real zeros.h(-x) has 1 variations in sign, h(x) has 1 negative real zero.

4

h(x) has 5 variation in sign, h(x) has 5 positive real zeros.h(-x) has 1 variations in sign, h(x) has 1 negative real zero.

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Multiple Choice

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1

𝒇(𝒙)=π’™πŸ’βˆ’πŸ’π’™πŸ‘βˆ’πŸπŸ‘π’™πŸ+πŸ“πŸ’π’™+πŸ•πŸπ’‡(𝒙)=𝒙^πŸ’βˆ’πŸ’π’™^πŸ‘βˆ’πŸπŸ‘π’™^𝟐+πŸ“πŸ’π’™+πŸ•πŸ  

2

𝒉(𝒙)=πŸπ’™πŸ’βˆ’πŸπŸπ’™πŸ‘+πŸπ’™πŸβˆ’πŸ’πŸ’π’™βˆ’πŸπŸ’π’‰(𝒙)=πŸπ’™^πŸ’βˆ’πŸπŸπ’™^πŸ‘+πŸπ’™^πŸβˆ’πŸ’πŸ’π’™βˆ’πŸπŸ’  

3

𝒉(𝒙)=βˆ’πŸπŸπ’™πŸ’+πŸπŸŽπ’™πŸ‘+πŸ‘π’™πŸβˆ’π’™+πŸπŸ–π’‰(𝒙)=βˆ’πŸπŸπ’™^πŸ’+πŸπŸŽπ’™^πŸ‘+πŸ‘π’™^πŸβˆ’π’™+πŸπŸ–  

12

Multiple Choice

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1

   𝐟(𝒙)=π’™πŸ‘+πŸ“π’™πŸβˆ’πŸ’π’™βˆ’πŸπŸ(𝒙)=𝒙^πŸ‘+πŸ“π’™^πŸβˆ’πŸ’π’™βˆ’πŸ  

2

  𝒇(𝒙)=π’™πŸ’βˆ’πŸ”π’™πŸ‘βˆ’πŸπŸ’π’™πŸβˆ’πŸπŸ“πŸ’π’™βˆ’πŸπŸ“πŸ“π’‡(𝒙)=𝒙^πŸ’βˆ’πŸ”π’™^πŸ‘βˆ’πŸπŸ’π’™^πŸβˆ’πŸπŸ“πŸ’π’™βˆ’πŸπŸ“πŸ“  

3

     π’ˆ(𝒙)=γ€–πŸπ’™γ€—πŸ‘βˆ’πŸ’π’™πŸ+πŸπŸ–π’™βˆ’πŸ‘πŸ”π’ˆ(𝒙)=γ€–πŸπ’™γ€—^πŸ‘βˆ’πŸ’π’™^𝟐+πŸπŸ–π’™βˆ’πŸ‘πŸ”  

13

Multiple Choice

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1

x=-4 , x=3 , x=1/2  , x=3-i as Zeros   

(x+4)(x-3)(x-1/2)(x-(3-i)) as Factors 

2

 x=-4 , x=3 , x=1/2  , x=3-i , x=3+i as Zeros   

(x+4)(x-3)(x-1/2)(x-(3-i))(x-(3+i)) as Factors 

14

Open Ended

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What can you said

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