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Topic Test 5 & 6 Review Part 1

Topic Test 5 & 6 Review Part 1

Assessment

Presentation

Mathematics

10th Grade

Easy

CCSS
HSG.SRT.B.5, 8.G.A.5, HSG.CO.B.7

+2

Standards-aligned

Created by

Larry Cooper

Used 12+ times

FREE Resource

11 Slides • 19 Questions

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Topic Test 5 & 6 Review Part 1

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Multiple Choice

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What is the #3 Reason? #2

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Alternate Exterior Angles

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Alternate Interior Angles

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Vertical Angles

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Angle Bisector

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Multiple Choice

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Are these triangles congruent? If so, state the rule which you used to determine congruence. #3

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SAS

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SSS

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Both SSS and SAS

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Not necessarily congruent

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Multiple Choice

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How are the two triangles congruent? #4

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SSS

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SAS

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ASA

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Not enough information

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Multiple Choice

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State if the 2 Δs are , and if so justify.State\ if\ the\ 2\ \Delta's\ are\ \cong,\ and\ if\ so\ justify.  #11

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 , SAS\cong\ ,\ SAS  

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, HL\cong,\ HL  

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not not\ \cong  

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, SSA\cong,\ SSA  

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Multiple Choice

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Determine if the 2 Δs are , if so, state the postulate used.Deter\min e\ if\ the\ 2\ \Delta's\ are\ \cong,\ if\ so,\ state\ the\ postulate\ used.  #12

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not , not enough informationnot\ \cong,\ not\ enough\ \inf ormation  

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, SAS\cong,\ SAS  

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not , need the 3rd side to be =not\ \cong,\ need\ the\ 3rd\ side\ to\ be\ =  

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, SSS\cong,\ SSS  

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Match

Match the following: Using the tick marks for each pair of triangles, match the method (SSS, SAS, or ASA), if any, that can be used to prove the triangles are congruent. #14

SSS

SAS

ASA

NONE

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Dropdown

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What is the reason for # 5? ​


What is the reason for #6? ​


What is the reason for #7? ​
​#16

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Match

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Match the following. #17

Draw BD parallel to AC.

m∠4+m∠2+m∠5=180∘

∠1≅∠4, ∠3≅∠5

m∠1=m∠4, m∠3=m∠5

m∠1+m∠2+m∠3=180∘

Parallel Postulate

Angle Addition Postulate and definition of straight edge

Alternate Interior Angles Theorem

Definition of congruent angles

Triangle Sum Theorem

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Multiple Select

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Select all of the true statements. #9

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statement #1

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statement #2

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statement #3

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statement #4

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statement #5

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Multiple Choice

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Find the measure of  CABFind\ the\ measure\ of\ \angle\ CAB  . #8

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13°13\degree  

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41°41\degree  

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87°87\degree  

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52°52\degree  

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Multiple Choice

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Solve for "y". #10

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No Clue

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11.8 in

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27 in

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19 in

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Dropdown

In an isosceles triangle that has exactly two equal sides, the equal sides are called legs, and the third side is called the base. The angle included by the legs is called the ​
angle, and the angles that have the base as one of their sides are called the ​
angle. ​  ​​ ​ ​#13

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Multiple Choice

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​Which of the following is the missing term in the proof? #20

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∠W

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∠X 

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∠Y

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∠Z

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Multiple Choice

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Use the image to answer the question. #24

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13

2

25

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53

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65

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Multiple Select

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If KM = 60 units, JK = 4x-10, and JL is a perpendicular bisector of JL determine which of the following values are correct. Select three that apply.

#25

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x=15x=15

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perimeter of ΔJKM=160 unitsperimeter\ of\ \Delta JKM=160\ units

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x=5x=5

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perimeter of ΔJML=90 unitsperimeter\ of\ \Delta JML=90\ units

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JK=50 units\overline{JK}=50\ units

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Drag and Drop

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What is the centroid (x,y) ( ​
, ​
)​ of the 3 given coordinates? #36Use the formula ((x1+x2+x3)/3, (y1+y2+y3)/3).

Drag these tiles and drop them in the correct blank above
-3
4
-4.5
3
-1.5
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Multiple Choice

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Find the coordinates of the centroid of ΔXYZ \Delta XYZ\   with X(-4,2), Y(0,5), and Z(3,-1). #38

Use the formula ((x1+x2+x3)/3, (y1+y2+y3)/3).

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(13,2)\left(\frac{-1}{3},2\right)  

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(13,2)\left(\frac{1}{3},2\right)  

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(13,2)\left(\frac{-1}{3},-2\right)  

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(13,12)\left(\frac{-1}{3},\frac{-1}{2}\right)  

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Reorder

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Reorder the steps for constructing a circumcenter of a triangle. #39

Draw the perpendicular bisectors of all the sides of the triangle using a compass.

Extend all the perpendicular bisectors to meet at a point. Mark the intersection point as O, this is the circumcenter.

Using a compass and keeping O as the center and any vertex of the triangle as a point on the circumference, draw a circle, this circle is our circumcircle whose center is O.

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Reorder

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Reorder the following steps for constructing an incenter of a triangle. #40

Bisect one of the angles.

Bisect another angle.

Where they cross is the center of the inscribed circle, called the incenter.

Construct a perpendicular from the center point to one side of the triangle.

Place compass on the center point, adjust its length to where the perpendicular crosses the triangle, and draw your inscribed circle!

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Topic Test 5 & 6 Review Part 1

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