
STAAR Review - Linear Functions
Presentation
•
Mathematics
•
9th Grade
•
Practice Problem
•
Hard
Standards-aligned
Eric Douce
Used 14+ times
FREE Resource
19 Slides • 5 Questions
1
Slope-Intercept Form: y = mx + b
Point-Slope Form: y - y1 = m(x -x1)
Standard Form: Ax + By = C
.
.
Parallel vs Perpendicular Lines
Unit 3: Linear Functions
2
Slope or Rate of Change (symbol = m)
3
Rise Over Run
Slope Equation
Slope or Rate of Change (symbol = m)
4
Rise over Run
Find the slope of this line
using rise over run.
5
Rise over Run
6
Slope Equation - Linear Regression
y1 ~ mx1+b
DESMOS
Add table
Input data
y1~mx1+b
7
Slope Equation - Linear Regression
y1 ~ mx1+b
DESMOS
Add table
Input data
y1~mx1+b
rate of change (m) = 7
8
Slope Equation
What is the slope of a line that passes through the points (5,-11) and (-9,17)?
HINT: Write the equation without the x1, y1, x2, and y2, then input coordinates or USE DESMOS.
DESMOS
Add table
Input data
y1~mx1+b
9
Slope Equation or
What is the slope of a line that passes through the points (5,-11) and (-9,17)?
HINT: Write the equation without the x1, y1, x2, and y2, then input coordinates or USE DESMOS.
Answer = -2
DESMOS
Add table
Input data
y1~mx1+b
10
Multiple Choice
What is the slope of a line that passes through the points (26,7) and (-39,12)?
Use DESMOS to solve and SIMPLIFY!!!
-1/13
5/13
-13
13/5
11
y = mx+b
m = slope
b = y-intercept
Slope-Intercept Form
Graph the line y = 3x - 2.
12
y = mx+b
m = slope
b = y-intercept
Slope-Intercept Form
Graph the line y = 3x - 2.
13
(y - y1) = m(x-x1)
m = slope
(x1, y1) = given point on line
Point-Slope Form
Given: point (3,-2), m = 1/2
Find the equation of a line in point-slope form.
HINT: Write the formula first without the x1 and y1, then input the coordinates.
14
(y - y1) = m(x-x1)
m = slope
(x1, y1) = given point on line
Point-Slope Form
15
(y - y1) = m(x-x1)
m = slope
(x1, y1) = given point on line
Point-Slope Form
Which equation is best represented by the graph?
A) y + 2 = 7/5 (x+7)
B) y - 2 = 7/5 (x-7)
C) y + 2 = 5/7 (x+7)
D) y - 2 = 5/7 (x-7
16
(y - y1) = m(x-x1)
m = slope
(x1, y1) = given point on line
Point-Slope Form
Which equation is best represented by the graph?
A) y + 2 = 7/5 (x+7)
B) y - 2 = 7/5 (x-7)
C) y + 2 = 5/7 (x+7)
D) y - 2 = 5/7 (x-7) - ANSWER
17
Multiple Choice
The graph of the linear function is shows on the grid.
Which equation is best represented by the graph?
y + 7 = -3(x-4)
y + 1 = -3(x+2)
y - 4 = 3(x+7)
y - 2 = 3(x-1)
18
Multiple Choice
Convert 2x - 5y = 10 into slope intercept form (y=mx+b)
y = 2x - 2
y = 2/5x - 2
or
y = 52x−2
y = -2x - 2
y = -2/5x - 2
or
y = −52x−2
19
Parallel vs. Perpendicular
Parallel Lines
Perpendicular Lines
lines with the same slope
.
y = 2/3x + 5
y = 2/3x - 7
lines with opposite reciprocals for slope
lines that intersect at a right angle
.
y = 1/4x + 1
y = -4x + 6
20
Multiple Choice
What is the equation of a line in slope-intercept form that passes through the point (5,0) and is parallel to the line represented by y = 1.2x + 3.8
y = 1.2x - 6
y = -1.2x + 6
y = 1.2x + 5
y = -1.2x - 5
21
Multiple Choice
What is the equation of a line in slope-intercept form that passes through the point (2,-2) and is perpendicular to the line represented by y = 2/5x + 2?
y = 5/2x - 7
y = 5/2x + 7
y = -5/2x - 3
y = -5/2x + 3
22
Inequalities
23
Inequalities
24
Inequalities
Slope-Intercept Form: y = mx + b
Point-Slope Form: y - y1 = m(x -x1)
Standard Form: Ax + By = C
.
.
Parallel vs Perpendicular Lines
Unit 3: Linear Functions
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