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  5. Solve Systems Of Equations Substitution 2
solve systems of equations substitution 2

solve systems of equations substitution 2

Assessment

Presentation

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Easy

•
CCSS
HSA.CED.A.3, L.1.1J, 8.EE.C.8B

+5

Standards-aligned

Created by

Patricia Carrow

Used 1+ times

FREE Resource

11 Slides • 6 Questions

1

Poll

How are you feeling today?

2

3

Open Ended

If your team wanted to try building something like this, what would you need to know?

4

​Let's say you have $1,000 to spend. (not much really). You have 2500 square feet to work with.

You think you would like to purchase some modules, each module has a specific size and cost.

Module A costs $200 per module and takes up 25 square feet

Module B costs $150 per module and takes up 50 square feet

5

​Let's say you have $1,000 to spend. (not much really). You have 2500 square feet to work with.

You think you would like to purchase some modules, each module has a specific size and cost.

Module A costs $200 per module and takes up 25 square feet

Module B costs $150 per module and takes up 50 square feet

​Let's look at the cost of each first and assume we will spend exactly $1000 (because we don't feel like dealing with inequalities yet)

6

Multiple Choice

Let's look at cost first and assume we will spend exactly $1000

Module A costs $200 per module

Module B costs $150 per module

Which equation represents this situation?

1

200A + 1000

= B

2

200A + 150B

= 1000

3

A + B =

1000

4

150B + 1000

= A

7

Multiple Choice

Next, consider the space constraints

You have 2500 square feet to work with.

Module A takes up 25 square feet

Module B takes up 50 square feet

Which equation represents this constraint?

1

25A + 50B

=2500

2

25A - 50B

= 2500

3

2500 + 50B

= 25A

4

A + B

=2500

8

​We now have a system of equations

​200A +150B = 1000

25A + 50B = 2500

9

Poll

Given this system of equations:

200A + 150B = 1000

25A +50B = 2500

Where would you like to start?

Solve for A in the first equation

Solve for A in the second equation

Solve for B in the first equation

Solve for B in the first equation

10

​200A + 150B = 1000

25A +50B = 2500

​you wanted to . . .

11

​200A + 150B = 1000

25A +50B = 2500

​Substitute into the other equation

12

​200A + 150B = 1000

25A +50B = 2500

​Solve for the chosen variable

13

​200A + 150B = 1000

25A +50B = 2500

​Solve for the other variable

14

​Let's say you have $1,000 to spend. (not much really). You have 2500 square feet to work with.

You think you would like to purchase some modules, each module has a specific size and cost.

Module A costs $200 per module and takes up 25 square feet

Module B costs $150 per module and takes up 50 square feet

​Answer the question in the context of the problem. We found that to spend exactly $1000 and use exactly 2500 square space you will need 88 A modules and 6 B modules.

15

Poll

If you needed to pay 10% sales tax and can't exceed $1000, what would you do?

Buy one less of module A

Buy one less of module B

Depends on how cool each module is

See what my team likes best

16

​Real problems get more complicated with multiple variables and constraints. Practice with the smaller ones to become comfortable with the bigger puzzles.

17

one last Rube before you go to practice

pattern-tertiary

How are you feeling today?

Show answer

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