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Factoring Review

Academic Algebra II

Mr. Grassel

Poll

How many of you remember reviewing Factoring at the beginning of the year during our Algebra 1 Review?

• I do!

• A little bit, but I could use more review

• Factoring?

Multiple Choice

Factor:
10x + 15

• 100x + 150
• 10(x + 5)
• 1(10x + 15)
• 5(2x + 3)

Multiple Choice

Factor:
x² - 5x

• 1(x - 5)
• x(x - 5x)
• x(x - 5)
• x²(1 - 5)

Multiple Choice

What is the GCF? 5x²+20x

• 5
• x
• 5x
• 20x

Multiple Choice

Factor q² - 121

• (q - 11) (q - 11)

• (q + 11) (q - 11)

• (q + 11) (q + 11)

• Can't factor using Diff. of Squares

Multiple Choice

Factor x² - 9

• (x + 3) (x - 3)

• (x - 3) (x - 3)

• (x + 3) (x - 6)

• Can't factor using Diff. of Squares

Multiple Choice

Factor

x² + 7x + 12

• (x + 2)(x + 10)

• (x + 3)(x + 4)

• (x + 4)(x + 5)

• (x + 4)(x + 6)

Multiple Choice

Factor completely:

y² - 7y + 12

• (y - 3) (y - 4)

• (y + 3) (y - 4)

• (y + 3) (y + 4)

• (y - 2) (y - 6)

Multiple Choice

x²+10x+16

• (x-2)(x-8)

• (x+2)(x+8)

• (x+1)(x+16)

• (x+6)(x+10)

Multiple Choice

Factor
k² -2k - 24

• (k+4)(k-6)
• (k+4)(k+6)
• (k+6)(k-1)
• (k-4)(k+6)

Poll

Which do you need the most help with?

• Factoring out a GCF

• Difference of Squares

• Factoring Trinomials

Poll

After reviewing basic factoring- on a scale of 1 to 4, how do you feel about factoring?

• 4- This is easy, I could teach it to the class

• 3- I am good most of the time

• 2- Ehhh, I can do it some times

• 1- What in the world is this? I wasn't here or coherent when we reviewed this

Algebra - Lesson Quadratic Equations

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Multiple Choice

Use the graph to determine the solutions.

• -1 and -3
• 1 and -3
• 1 and 3
• -1 and 3

Multiple Choice

Solve the following quadratic by looking for the zeros.

2x² - 3x - 2 = 0

• x = 1, x = -1

• x = -1/2, x = 2

• x = 1/2, x = 2

• x = 1/2, x = 1

Multiple Choice

Solve. Remember, it must be equal to zero before you can solve.

x² + 4x= 12

• x = 2 and -2

• x = -6 and 2

• x = 6 and -2

• x = 1 and -1

Algebra 2 4.5, 4.8 Review

​Simplifying Square Roots

​Simplifying Complex Number Expressions

Conjugates

No i's can be left in the denominator.

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​Use the conjugate to eliminate the i in the denominator.

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​The conjugate is the expression with the same terms but a different sign.

Solving by Factoring and Square Roots

Factoring can be used when you have an x term.

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​Square root can be used when you DO NOT have an x term.

Multiple Choice

How would you solve this problem?

$$6x^2-13x=5$$  

• Square Root method

• Factoring Method

Multiple Choice

Solve this problem.

$$6x^2-13x=5$$  

• $$x=-\frac{1}{3},\ \frac{5}{2}$$  

• $$x=\frac{1}{3},\ -\frac{5}{2}$$  

• $$x=-2,\ 15$$  

• none of these

Multiple Choice

How would you solve this problem?

$$64x^2=49$$  

• Square Root method

• Factoring Method

Multiple Choice

Solve this problem.

$$64x^2=49$$  

• $$x=\frac{7}{8}$$  

• $$x=\pm\frac{7}{8}$$  

• $$x=\pm\frac{8}{7}$$  

• $$x=\pm\frac{49}{64}$$  

Multiple Choice

How would you solve this problem?

$$3x^2+36=0$$  

• Square Root method

• Factoring Method

Multiple Choice

Solve this problem.

$$3x^2+36=0$$  

• $$x=\pm12$$  

• $$x=\pm12i$$  

• $$x=\pm2i\sqrt[]{3}$$  

• $$x=\pm4i\sqrt[]{3}$$  

Multiple Choice

How would you solve this problem?

$$10x^2-35x=0$$  

• Square Root method

• Factoring Method

Multiple Choice

Solve this problem.

$$10x^2-35x=0$$  

• $$x=\pm5$$  

• $$x=\pm\frac{7}{2}$$  

• $$x=0,\ \frac{7}{2}$$  

• $$x=0,\ \frac{5}{2}$$