Law of Sines

6.1 Law of Sines

Law of Sines

- must have 2 angles in the triangle

- side lengths are OUTSIDE the triangle

- angle measures are INSIDE the triangle

- ALWAYS START WITH YOUR SIDE LENGTHS AND THEN FIND THE ANGLE MEASURES OPPOSITE THAT SIDE LENGTH

Please change 19 m for side BC to 21 meters! Thanks!

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Watch the video if you missed the previous problem.

• If you got the problem correct, you may skip this video.

Multiple Choice

Which equation shows how you would use the law of sines to find side c?

• $$\frac{\sin41}{19}=\frac{\sin\ 75}{c}$$

• $$\frac{\sin\ 64}{19}=\frac{\sin\ 75}{c}$$

• $$\frac{\sin\ 19}{64}=\frac{\sin\ c}{75}$$

• $$\frac{\sin19}{41}=\frac{\sin\ c}{75}$$

Multiple Choice

Find AC. Round your answer to the nearest whole number.

• 12

• 10

• 23

• 14

Multiple Choice

Find AB. Round your answer to the nearest whole number.

• 10

• 8

• 6

• 5

Multiple Choice

calculate angle C

• 43

• 70

• 63

• 47

Multiple Choice

If angle C=70 mm calculate  side b

• 70 mm

• 42.7 mm

• 45.8 mm

• 43 mm

Fill in the Blank

Find c to the nearest tenth.