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Algebra 2 Recovery - U1

Algebra 2 Recovery - U1

Assessment

Presentation

Mathematics

10th Grade

Medium

Created by

Henry Phan

Used 4+ times

FREE Resource

30 Slides • 30 Questions

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Multiple Choice

Question 1: Power i

simplify it

i130i^{130}  = ?

1

ii  

2

i-i  

3

1

4

-1

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Multiple Choice

Question 2: Power i

simplify it

i141i^{141}  = ?

1

ii  

2

i-i  

3

1

4

-1

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Multiple Choice

Question 3: Power i

simplify it

i152i^{152}  = ?

1

ii  

2

i-i  

3

1

4

-1

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Multiple Choice

Question 4: Power i simplify it

i163i^{163}  = ?

1

ii  

2

i-i  

3

1

4

-1

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Multiple Choice

Question 5: {4 cases: a = a + 0i, -a = -a + 0i, bi = 0 + bi, -bi = 0 - bi}

Choose the equivalent complex form to rewrite the given following:

πi\pi i  

1

 = π\pi  - 0i0i  

2

 = π\pi  + 0i0i  

3

 = 0 + πi\pi i  

4

 = 0 - πi\pi i  

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Multiple Choice

Question 6: {4 cases: a = a + 0i, -a = -a + 0i, bi = 0 + bi, -bi = 0 - bi}

Choose the equivalent complex form to rewrite the given following:

πi-\pi i  

1

 = π\pi  - 0i0i  

2

 = π\pi  + 0i0i  

3

 = 0 + πi\pi i  

4

 = 0 - πi\pi i  

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Multiple Choice

Question 7: {4 cases: a = a + 0i, -a = -a + 0i, bi = 0 + bi, -bi = 0 - bi}

Choose the equivalent complex form to rewrite the given following:

i5i\sqrt[]{5}  

1

 = 5\sqrt[]{5}   - 0i0i  

2

 = 5\sqrt[]{5}   + 0i0i  

3

 = 0 + i5i\sqrt[]{5}   

4

 = 0 - i5i\sqrt[]{5}   

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Multiple Choice

Question 8: {4 cases: a = a + 0i, -a = -a + 0i, bi = 0 + bi, -bi = 0 - bi}

Choose the equivalent complex form to rewrite the given following:

5-\sqrt[]{5}  

1

 = 5-\sqrt[]{5}   - 0i0i  

2

 = 5\sqrt[]{5}   + 0i0i  

3

 = 0 + i5i\sqrt[]{5}   

4

 = 0 - i5i\sqrt[]{5}   

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Multiple Choice

Question 9: Radical of negative numbers { a = ia\sqrt[]{-a}\ =\ i\sqrt[]{a} }

50\sqrt{-50}  =

1

5i25i\sqrt{2}  

2

i5i\sqrt{5}   

3

2i52i\sqrt{5}  

4

25i225i\sqrt{2}  

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Multiple Choice

Question 10: Radical of negative numbers { a = ia\sqrt[]{-a}\ =\ i\sqrt[]{a} }

243\sqrt{-243}  =

1

3i33i\sqrt{3}  

2

9i39i\sqrt{3}  

3

81i381i\sqrt{3}  

4

3i813i\sqrt{81}  

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Multiple Choice

Question 11: Simply the complex operations following:

(7 + 2i) - (-12 - 4i)

1

-5 - 2i

2

19 - 2i

3

-5 + 6i

4

19 + 6i

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Multiple Choice

Question 12: Simply the complex operations following:

(5-2i) + (-7+8i)

1

-2+6i

2

12+6i

3

-35-16i2

4

-35 -16i

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Multiple Choice

Question 13: Simply the complex operations following:

  (10+ 15i) - (48 - 30i)

1

58 - 45i

2

58 - 15i

3

-38 - 15i

4

-38 + 45i

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Multiple Choice

Question 14: Simply the complex operations following:

(16i) + (72i)\left(-1-6i\right)\ +\ \left(-7-2i\right)  

1

72i-7-2i  

2

88i-8-8i  

3

6+4i6+4i  

4

68i6-8i  

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Multiple Choice

Question 15: {Distributive product and treat i like x}

-4(2 - 3i)

1

-8 + 12i

2

8 - 12i

3

20i

4

-4i

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Multiple Choice

Question 16: {Distributive product and treat i like x}

-2(4 - 5i)

1

-8 + 10i

2

8 - 10i

3

-18i

4

2i

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Multiple Choice

Question 17: {Distributive product and treat i like x}

(12i)(66i)\left(-1-2i\right)\left(-6-6i\right)  

1

7+16i-7+16i  

2

24+24i24+24i  

3

12+12i12+12i  

4

6+18i-6+18i  

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Multiple Choice

Question 18: {Distributive product and treat i like x}

(4+6i)(6+4i)\left(4+6i\right)\left(-6+4i\right)  

1

5416i-54-16i  

2

52i-52i  

3

52i52i  

4

4820i-48-20i  

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Multiple Choice

Question 19: {Just change operation of imagine "i" from positive to negative or the other way around}

2 - 3i

1

-2 + 3i

2

2 + 3i

3

-2 - 3i

4

2 - 3i

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Multiple Choice

Question 20: {Just change operation of imagine "i" from positive to negative or the other way around}

6i + 2

1

-6i - 2

2

-6i + 2

3

6i + 2

4

2 + 6i

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Multiple Choice

Question 21: {Multiply with the conjugate of the give denominator for top and bottom for the following expression}

Simplify: 52 + 3i\frac{-5}{2\ +\ 3i}  

1

1015i49i\frac{-10-15i}{4-9i}  

2

10 + 15i13\frac{-10\ +\ 15i}{13}  

3

10 + 15i4 +9i\frac{10\ +\ 15i}{4\ +9i}  

4

10 + 15i13\frac{10\ +\ 15i}{13}  

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Multiple Choice

Question 22: {Multiply with the conjugate of the give denominator for top and bottom for the following expression}

Simplify: 3+2i5 3i\frac{3+2i}{5\ -3i}  

1

21 i34\frac{21\ -i}{34}  

2

21+i34\frac{21+i}{34}  

3

9 19i34\frac{9\ -19i}{34}  

4

9+19i34\frac{9+19i}{34}  

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Multiple Choice

Question 23: {Isolate for x, then taking square-root for both sides. Remember x with have two [positive and negative] solutions}

Solve by for x:

2x2 = 18

1

x = 5 or -5

2

x = 3 or -3

3

x = 7 or -3

4

x = -7 or 3

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Multiple Choice

Question 24: {Isolate for x, then taking square-root for both sides. Remember x with have two [positive and negative] solutions}

Solve for x:

x2 - 1 = 48

1

x=7,12

2

x=±7

3

x=1,-13

4

x=43,-55

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Multiple Choice

Question 25:

two roots x = 2 and x = -1 . Determine the matching quadratic equation

(hint you will work backward: (x - 2)(x + 1)

1

x2 + 3x - 2

2

x2 - 3x - 2

3

x2 + x - 2

4

x2 - x - 2

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Multiple Choice

Question 26:

Solve for x by factoring: x2 - 13 = 0

1

(x - 13)(x + 13)

then

x =13 and x = -13

2

(x - 13\sqrt[]{13}  )(x + 13\sqrt[]{13}  

then

x = 13\sqrt[]{13}  and x = 13-\sqrt[]{13}  

3

(x - i13i\sqrt[]{13}  )(x + i13i\sqrt[]{13}  

then

x = i13i\sqrt[]{13}  and x = i13-i\sqrt[]{13}  

4

(x - 6)(x - 7)

then

x =6 and x = 7

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Multiple Choice

Question 27: Solve for x by Factoring

x2 - 8x + 15 = 0

1

(x + 5) ( x + 3)

then

x = -5 and x = -3

2

(x - 5) (x - 3)

then

x = 5 and x = 3

3

(x + 15) (x - 1)

then

x = -15 and x = 1

4

(x - 5) (x + 3)

then

x = 5 and x = -3

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Multiple Choice

Question 28:

Solve for k by Factoring

k2 + 12k + 35 = 0

1

(k + 5)(k + 7)

Thus,

k = -5 and k = -7

2

(k + 4)(k + 3)

Thus,

k = -4, and k = -3

3

(k + 7)(k - 5)

Thus,

k = -7, and k = 5

4

(k + 3)(k + 5)

Thus,

k = -3 and k = -5

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Multiple Choice

Identify a, b and c in the quadratic equation: 2x23x5=02x^2-3x-5=0  

1

a = 2 , b = 3, c = -5

2

a = 2, b = -3, c = 5

3

a = 2, b = -3, c = -5

4

a = -2, b = 3, c = 5

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Multiple Choice

Using the calculator to solve it:

15x2 + x - 2 = 0

1

Two real solution:

x = -1/3

x = 2/5

2

Two real solution:

x = 1/3

x = -2/5

3

Two complex solution:

x = -1/3 + i

x = 2/5 - i

4

Two complex solution:

x = 1/3 + i

x = -2/5 - i

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