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9.2 The Hyperbola

9.2 The Hyperbola

Assessment

Presentation

Mathematics

11th Grade

Easy

MGSE9-12.G.GPE.3

Standards-aligned

Created by

Larry Cooper

Used 2+ times

FREE Resource

9 Slides • 18 Questions

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9.2 The Hyperbola

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3

Multiple Choice

Question image

What is the "a" value of this hyperbola? #12

1

5

2

6

3

3

4

4

5

7.5

4

5

Multiple Choice

Question image

What are the vertices of the hyperbola? #5

1

(0, 3) and (0, -3)

2

(-4, 3) and (-4, -3)

3

(0, 1) and (0, -1)

4

(4, 0) and (-4, 0)

6

Multiple Choice

What is the equation describing the relationship between dimensions and foci of a hyperbola? #1

1

c2 = a2 + b2

2

c2 = a2 - b2

3

4p

4

(x-h)2 + (y-k)2 = r2

7

8

9

Multiple Choice

A hyperbola has vertices (±5, 0) and one focus at (6, 0). What is the equation of the hyperbola in standard form? #6

1

x²/25 + y²/11 = 1

2

x²/5 - y²/11 = 1

3

x²/11- y²/25 = 1

4

x²/25 - y²/11= 1

10

Multiple Choice

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Find the equation of a hyperbola. #7

1

(x - 2)2 / 16 - (y + 3)2 / 20 = 1

2

(x + 3)2 / 16 - (y - 2)2 / 20 = 1

3

(x - 2)2 / 20 - (y + 3)2 / 16 = 1

4

(y + 3)2 / 16 - (x - 2)2 / 20 = 1

11

Multiple Choice

The vertices of a hyperbola are located at (1,1) and (5,1). Which are the coordinates of the center? #10

1

(3,1)

2

(3,0)

3

(1,3)

4

(9,1)

12

13

Multiple Choice

Question image

What is the "b" value of this hyperbola? #13

1

3

2

5

3

4

4

6

5

7.5

14

Multiple Choice

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Is the hyperbola vertical or horizontal? #3

1

Vertical

2

Horizontal

15

Multiple Choice

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What is the value of a2 for the given hyperbola? #8

1

1

2

5

3

25

4

16

16

Multiple Choice

What are the foci of the hyperbola with the equation y²/12 - x²/5 = 1? #2

1

(0, ±√17)

2

(±√17, 0)

3

(0, ±√7)

4

(±√7, 0)

17

18

Multiple Choice

A hyperbola centered at (-3, 2) with a horizontal transverse axis has asymptotes y = ± ¾x.  Which of the following could be the equation of the hyperbola in standard form? #9

1

(x + 3)2/16 + (y - 2)2/ 9 = 1

2

(x + 3)2/ 4 - (y - 2)2/ 3 = 1

3

(x + 3)2/16 - (y - 2)2/ 9 = 1

4

(x + 3)2/ 9 - (y - 2)2/ 16 = 1

19

Multiple Choice

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What is the eccentricity of the hyperbola? #17

1

1.17

2

1.38

3

2.25

4

3.14

5

0.89

20

21

Multiple Choice

Question image

What is the "c" value of this hyperbola? #14

1

5.83

2

4.45

3

3.34

4

6.5

5

7.25

22

Multiple Choice

Question image

What is the graph of this hyperbola? #16

1
2
3
4
5

23

Multiple Choice

Which graph represents (y1)216(x+1)24=1\frac{\left(y-1\right)^2}{16}-\frac{\left(x+1\right)^2}{4}=1  ? #21

1
2
3
4

24

25

Multiple Choice

Write the equation of the hyperbola: #22

Vertices: (5, 14) and (5, -4)

Length of conjugate axis = 16 units

1

(y5)281(x5)264=1\frac{\left(y-5\right)^2}{81}-\frac{\left(x-5\right)^2}{64}=1  

2

(y5)264(x5)281=1\frac{\left(y-5\right)^2}{64}-\frac{\left(x-5\right)^2}{81}=1  

3

(x5)264(y5)281=1\frac{\left(x-5\right)^2}{64}-\frac{\left(y-5\right)^2}{81}=1  

4

(y5)281(x+5)264=1\frac{\left(y-5\right)^2}{81}-\frac{\left(x+5\right)^2}{64}=1  

26

Multiple Choice

Write the equation of the hyperbola given: #23

Vertices: (1, -3) and (-7, -3)

Asymptotes: y=±32(x+3)3y=\pm\frac{3}{2}\left(x+3\right)-3  

1

(x+3)236(y+3)216=1\frac{\left(x+3\right)^2}{36}-\frac{\left(y+3\right)^2}{16}=1  

2

(x+3)216(y+3)236=1\frac{\left(x+3\right)^2}{16}-\frac{\left(y+3\right)^2}{36}=1  

3

(y+3)236(x+3)216=1\frac{\left(y+3\right)^2}{36}-\frac{\left(x+3\right)^2}{16}=1  

4

(x+3)236(y3)216=1\frac{\left(x+3\right)^2}{36}-\frac{\left(y-3\right)^2}{16}=1  

27

Multiple Choice

Write the equation of the hyperbola given: #24

Foci: (1,2±265)\left(-1,2\pm\sqrt[]{265}\right)  

Eccentricity: e=26511e=\frac{\sqrt[]{265}}{11}  

1

(x+1)2121(y2)2144=1\frac{\left(x+1\right)^2}{121}-\frac{\left(y-2\right)^2}{144}=1  

2

(y2)2121(x+1)2144=1\frac{\left(y-2\right)^2}{121}-\frac{\left(x+1\right)^2}{144}=1  

3

(y2)29(x+1)2100=1\frac{\left(y-2\right)^2}{9}-\frac{\left(x+1\right)^2}{100}=1  

4

(y2)2121(x+1)29=1\frac{\left(y-2\right)^2}{121}-\frac{\left(x+1\right)^2}{9}=1  

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9.2 The Hyperbola

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