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Using square roots to solve equations

Using square roots to solve equations

Assessment

Presentation

Mathematics

6th Grade

Practice Problem

Easy

CCSS
8.EE.A.2, HSA-REI.B.4B, 6.EE.A.1

Standards-aligned

Created by

Ms. Blondin

Used 3+ times

FREE Resource

4 Slides • 25 Questions

1

Finding a square root to solve problems

media

Fluency and Practice - Lesson 23

2

Multiple Choice

64\sqrt[]{64} = ?

1

7

2

8

3

9

4

10

3

Multiple Choice

49\sqrt[]{49} = ?

1

7

2

8

3

9

4

10

4

Multiple Choice

100\sqrt[]{100} = ?

1

7

2

8

3

9

4

10

5

Multiple Choice

x2\sqrt[]{x^2} = ?

1

x

2

8

3

x2x^2

4

100

6

The square root of any variable that is squared will be itself.

You can find the square root of numbers on both sides of the equal sign to keep the equation balanced

Solving for an unknown variable

7

Your answer can be positive or negative

8

Drag and Drop

x2 =100x^2\ =100 ​ ​
Drag these tiles and drop them in the correct blank above
x = -10

9

Dropdown

How do I solve for y?

y2 = 81y^2\ =\ 81

10

Dropdown

How do I solve for b​
? b2 = 25b^2\ =\ 25

11

Dropdown

solve for b​

b2 = 25b^2\ =\ 25 ​​ ​
Hint: There is one answer that is

12

Multiple Choice

Solve: x2= 64x^2=\ 64

1

x = -8

2

x = 32

3

x = ±8\pm8

4

x = 8

13

Multiple Choice

How do you solve: a2 = 149a^2\ =\ \frac{1}{49}

1

a2=149\sqrt[]{a^2}=\sqrt[]{\frac{1}{49}}

2

a2= 149\sqrt[]{a^2}=\ \frac{1}{\sqrt[]{49}}

3

a=49\sqrt[]{a}=\sqrt[]{49}

4

a = 49

14

Multiple Choice

Solve: a2 = 149a^2\ =\ \frac{1}{49}

1

a = 17a\ =\ -\frac{1}{7}

2

a = 17\frac{1}{7}

3

a = 7

4

a = ±17a\ =\ \pm\frac{1}{7}

15

Multiple Choice

Solve: y2= 81y^2=\ 81

1

y = -9

2

y = 19\frac{1}{9}

3

y = ±9y\ =\ \pm9

4

y = 19-\frac{1}{9}

16

Match

Match the following

42=-4^2= ?

72 =-7^2\ = ?

112-11^2 = ?

152-15^2 = ?

22-2^2 = ?

16

49

121

225

4

17

Multiple Choice

Solve: p2 =1121p^2\ =\frac{1}{121}

1

p = -11

2

p =  111-\ \frac{1}{11}

3

p = ±11p\ =\ \pm11

4

p = ±111p\ =\ \pm\frac{1}{11}

18

Multiple Choice

m2 = 916m^2\ =\ \frac{9}{16}

1

m = ±34\pm\frac{3}{4}

2

p = 916\frac{9}{16}

3

p = 9

4

p = 34\frac{3}{4}

19

Match

Match the following

16\sqrt[]{16}

36\sqrt[]{36}

196\sqrt[]{196}

169\sqrt[]{169}

1\sqrt[]{1}

4 or -4

-6 or 6

-14 or 14

13 or -13

1 or -1

20

Multiple Choice

Solve: k2 = 25144k^2\ =\ \frac{25}{144}

1

k = 25

2

k = 144

3

k = 512\frac{5}{12}

4

k = ±512k\ =\ \pm\frac{5}{12}

21

Up Next... 2 step equations

22

Multiple Choice

Let's try one:

What is the first step to solve this equation?

d2  2 = 7d^2\ -\ 2\ =\ 7

1

find the square root of both sides

2

subtract 2 from both sides

3

add 2 to both sides

4

subtract 7 from both sides

23

Multiple Choice

Let's try one:

What is the second step to solve this equation?

d2  2 = 7d^2\ -\ 2\ =\ 7

d2 = 9d^2\ =\ 9

1

find the square root of both sides

2

subtract 9 from both side

3

add 9 to both sides

4

square both sides

24

Multiple Choice

Let's try one:

Solve:

d2  2 = 7d^2\ -\ 2\ =\ 7

d2 = 9d^2\ =\ 9

1

d = 9

2

d = -3

3

d = ±9\pm9

4

d = ±3\pm3

25

Multiple Choice

Let's try one:

What is the first step to solve this equation?

f2  12 = 132f^2\ -\ 12\ =\ 132

1

find the square root of both sides

2

subtract 12 from both sides

3

add 12 to both sides

4

subtract 132 from both sides

26

Multiple Choice

Let's try one:

What is the second step to solve this equation?

f2  12 = 132f^2\ -\ 12\ =\ 132

f2 = 144f^2\ =\ 144

1

divide both sides by 2

2

combine like terms

3

subtract 144 from both sides

4

find the square root of both sides

27

Multiple Choice

Let's try one:

Solve:

f2  12 = 132f^2\ -\ 12\ =\ 132

f2 = 144f^2\ =\ 144

1

f = 144

2

f = ±12\pm12

3

f = -12

4

f = 12

28

Math Response

What is the first step to solve this? x2=256x^2=256

Type answer here
Deg°
Rad

29

Poll

How comfortable are you with solving equations using squares and square roots?

I'm still not really getting it

I need some more practice but I'm starting to understand

I'm pretty sure I can do some simple problems on my own

I've got this! Give me the test!

Finding a square root to solve problems

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Fluency and Practice - Lesson 23

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