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(4) Trigonometri

(4) Trigonometri

Assessment

Presentation

•

Mathematics

•

10th Grade

•

Practice Problem

•

Medium

Created by

Sepka Sugita

Used 2+ times

FREE Resource

8 Slides • 5 Questions

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Multiple Choice

Berikut identitas kebalikan yang tepat dari sec⁡α\sec\alpha adalah ....

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1sec⁡α\frac{1}{\sec\alpha}

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1cosec⁡α\frac{1}{\operatorname{cosec}\alpha}

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1cos⁡α\frac{1}{\cos\alpha}

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1sin⁡α\frac{1}{\sin\alpha}

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Multiple Choice

Berikut identitas perbandingan yang tepat dari sin⁡αcos⁡α\frac{\sin\alpha}{\cos\alpha} adalah ....

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tan⁡α\tan\alpha

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cotan⁡α\operatorname{cotan}\alpha

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sec⁡α\sec\alpha

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cosec⁡α\operatorname{cosec}\alpha

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Multiple Choice

Langkah pertama untuk membuktikan identitas trigonometri

1+tan⁡2 αtan⁡2 α(1+cotan⁡2 α)=1\frac{1+\tan^2\ \alpha}{\tan^2\ \alpha\left(1+\operatorname{cotan}^2\ \alpha\right)}=1

adalah ....

1

cos⁡2 α(sec⁡2 α−1)(cosec⁡2 α)=1\frac{\cos^2\ \alpha}{\left(\sec^2\ \alpha-1\right)\left(\operatorname{cosec}^2\ \alpha\right)}=1

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sec⁡2 α(sec⁡2 α−1)(cosec⁡2 α)=1\frac{\sec^2\ \alpha}{\left(\sec^2\ \alpha-1\right)\left(\operatorname{cosec}^2\ \alpha\right)}=1

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sec⁡2 α(sec⁡2 α−1)(sec⁡2 α)=1\frac{\sec^2\ \alpha}{\left(\sec^2\ \alpha-1\right)\left(\sec^2\ \alpha\right)}=1

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sec⁡2 α(cotan⁡2 α−1)(cosec⁡2 α)=1\frac{\sec^2\ \alpha}{\left(\operatorname{cotan}^2\ \alpha-1\right)\left(\operatorname{cosec}^2\ \alpha\right)}=1

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