
GEOMETRI
Presentation
•
Others
•
9th - 12th Grade
•
Hard
ACHMAD MUJAHID
Used 2+ times
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16 Slides • 5 Questions
1
BY ACHMAD MUJAHID
2
TUJUAN PEMBELAJARAN
Siswa dapat menyelesaikan masalah berkaitan dengan geometri
3
4
adalah bangun ruang yang dibatasi oleh 2 buah sisi / bidang sejajar serta beberapa sisi yang berpotongan menurut garis-garis yang sejajar
sifat-sifat : sisi alas dan sisi atas bentuk dan ukurannya sama dan sejajar, sisi tegak yang berbentuk persegi panjang, jarak antara sisi alas dan sisi atas disebut tinggi prisma
Volume Prisma segitiga = A (Luas alas) x t (tinggi prisma)
Volume Balok = p x l xt
Volume kubus = sisi x sisi x sisi
Jenis-jenis :
5
Banyak sisi tegak : 3
Jumlah sisi : 5
Jumlah rusuk : 9
Banyak titik sudut : 6
6
Volume kubus (Prisma segi 4)
= s x s x s
= 12 cm x 12 cm x 12 cm
= 1.780 cm3
Banyak sisi tegak : 4
Jumlah sisi : 6
Jumlah rusuk : 12
Banyak titik sudut : 8
7
Volume balok
= p x l x t
= 9 cm x 5 cm x 6 cm
= 270 cm3
Banyak sisi tegak : 4
Jumlah sisi : 6
Jumlah rusuk : 12
Banyak titik sudut : 8
8
9
Tabung :
Banyak sisi : 3
Banyak rusuk : 2
Banyak titik sudut : -
10
11
Limas segi empat
Banyak sisi tegak : 4
Jumlah sisi : 5
Jumlah rusuk : 8
12
13
Kerucut :
Banyak sisi : 2
Banyak rusuk : 1
Jumlah rusuk : 12
14
15
Bola
Banyak sisi : 1
Banyak rusuk : 6
Banyak titik sudut : -
16
Multiple Choice
Ukuran prisma tersebut adalah ....
tprisma = 20 cm
tΔ = 13 cm
aΔ = 5 cm
tprisma = 20 cm
tΔ = 12 cm
aΔ = 5 cm
tprisma = 20 cm
tΔ = 12 cm
aΔ = 13 cm
17
Multiple Select
Volume kubus tersebut adalah = ....
V. Kubus = 6 m x 6 m x 6 m = 216 m3
V. Kubus = 6 m + 6 m + 6 m = 18 m
V. Kubus = (6m)3 = 216 m3
V. Kubus = 6 m3
18
Multiple Select
Ukuran prisma tersebut adalah ....
tprisma = 12 cm
tΔ = 4 cm
aΔ = 6 cm
tprisma = 12 cm
tΔ = 5 cm
aΔ = 6 cm
V. Prisma = (½ x 6cm x 4cm) x 12cm = 144 cm3
V. Prisma = (½ x 6cm x 5cm) x 12cm = 180 cm3
V. Prisma = (½ x 6cm x 5cm) x 12cm = 180 cm3
19
Multiple Choice
Ukuran tabung tersebut adalah ....
t = 20 cm
d = 10 cm
r = 5 cm
t = 20 cm
r = 10 cm
d = 5 cm
20
Multiple Select
Volume dan luas permukaan kerucut tersebut adalah ....
V = 8. 792 cm3
V = 8.972 cm3
Lp = 3.077,2 cm2
Lp = 2.574,8 cm2
Lp = 2.574,8 cm2
21
BY ACHMAD MUJAHID
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