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Trigonometry review and Reference Angle check

Trigonometry review and Reference Angle check

Assessment

Presentation

•

Mathematics

•

12th Grade

•

Practice Problem

•

Easy

•
CCSS
8.G.B.8, HSG.SRT.C.8, 8.G.B.7

+2

Standards-aligned

Created by

Anonymous Anonymous

Used 4+ times

FREE Resource

1 Slide • 17 Questions

1

Poll

How well do you remember special right triangles?

Very well

Here and there

Hmm, I have to think about that

Totally forgotten the concept

2

Multiple Choice

Question image

Find the missing side lengths

1

a = 4, b = 2√2

2

a = 4, b = 4

3

a = 2√2,  b = 4

4

a = 4, b = 3

3

Math Response

You are making a guitar pick that resembles an equilateral triangle with side lengths of 32 millimeters. What is the approximate height of the pick? (hint: use 30-60-90 theorems) ​ ​ ​ ​

Type answer here
Deg°
Rad

4

Open Ended

are − 3π4\frac{3\pi}{4} and 5π4\frac{5\pi}{4} coterminal angles? Show your work to verify your answer

5

Math Response

What is cos 5π6\frac{5\pi}{6}

Type answer here
Deg°
Rad

6

Multiple Choice

What is the reference angle for 485°?

1

-75

2

75

3

55

4

125

7

Math Response

Find the reference angle in Radians

Type answer here
Deg°
Rad

8

Multiple Select

Which of the following angles are coterminal to the angle −5π3-\frac{5\pi}{3} ? Select all that apply.

1

π3\frac{\pi}{3}

2

7π3\frac{7\pi}{3}

3

−11π3-\frac{11\pi}{3}

4

−15π3-\frac{15\pi}{3}

9

Multiple Choice

Find an angle coterminal with an angle measuring radians. Show all work in the note you will submit on Google Classroom

1

π3\frac{\pi}{3}

2

5π4\frac{5\pi}{4}

3

5π3\frac{5\pi}{3}

4

π4\frac{\pi}{4}

10

Review Trig Identities

11

Poll

How well do you recall Trig Identities?

Boss Level

Hmm.. somewhere here or there

Vague collection

No idea what this is

12

Multiple Choice

cot⁡2x+1\cot^2x+1

1

sin⁡2x\sin^2x

2


csc⁡2x\csc^2x

3

1

4

cos⁡2x\cos^2x

13

Multiple Choice

csc x. cos x

1

sin x

2

1

3

cot x

4

tan x

14

Math Response

(sin⁡2x−cos⁡2x)(sec⁡2x−tan⁡2x)(csc⁡2x−cot⁡2x)\left(\sin^2x-\cos^2x\right)\left(\sec^2x-\tan^2x\right)\left(\csc^2x-\cot^2x\right)

Type answer here
Deg°
Rad

15

Multiple Choice

Simplify cot⁡θsin⁡θ\cot\theta\sin\theta

1

sin⁡2θ\sin^2\theta

2

cos θ\theta

3

tan θ\theta

4

1- sin⁡2θ\sin^2\theta

16

Multiple Choice

sec⁡2θ−1sec⁡2θ\frac{\sec^2\theta-1}{\sec^2\theta}

1
1
2


cos⁡2θ\cos^2\theta

3

sin⁡2θ\sin^2\theta

4

1 -sin θ\theta

17

Multiple Choice

csc⁡2θ−cot⁡2θ\csc^2\theta-\cot^2\theta

1

sec θ\theta

2

sec⁡2θ\sec^2\theta

3

csc⁡2x−1\csc^2x-1

4

1

18

Multiple Choice

sec⁡ x+ 1cos⁡ x\sec\ x+\ \frac{1}{\cos\ x}

1
1
2

0

3

2cos⁡ x\frac{2}{\cos\ x}

4

sec⁡2x\sec^2x

pattern-tertiary

How well do you remember special right triangles?

Very well

Here and there

Hmm, I have to think about that

Totally forgotten the concept

Show answer

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Slide 1 / 18

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