Distributive Property of Multiplication

What am I
learning today?

How to use the
distributive property
to find the area of a
rectangle

Why am I
learning it?

So I can use another
strategy to solve
multiplication
problems

How will I know
that I have
learned it?

I can find the area of a
large rectangle by dividing it
into two smaller rectangles
and then adding their areas
together.

Review: What is area?

3

6

3 x 6 = 18 sq. units

Multiple Choice

What is the area of this rectangle?

• 6 sq. feet

• 8 sq. feet

• 8

• 6

Multiple Select

What expressions could you use to find the area of this rectangle?

• $$5\ \times8$$

• $$8+8+8+8+8$$

• $$8+5$$

• $$5\times8$$

Damian wants to find the area of this

rectangle, but he doesn’t know the

answer to 5 x 12.

5

12

Damian divides his rectangle into two

pieces.

5

12

Instead of finding the area of the whole rectangle, he can find the area of the two smaller rectangles and add them together.

5

12

10

2

The red piece is 5 x 10
The blue piece is 5 x 2

5

12

10

2

So, 5 x 12 = (5 x 10) + (5 x 2)

5

12

10

2

The area is 50 + 10 = 60 sq. units

5

12

10

2

Multiple Select

Which expressions could you use to find the area of this rectangle?

• $$6\times6$$

• $$\left(5\times6\right)\ +\ \left(1\times6\right)$$

• $$30+6$$

• $$\left(6\times6\right)\ +\left(1\times6\right)$$

Fill in the Blanks

Multiple Select

What expressions could you use to find the area of this rectangle?

• $$\left(5\times5\right)+\left(8\times3\right)$$

• $$\left(5\times5\right)\ +\ \left(3\times5\right)$$

• $$25+15$$

• $$50\ +8$$

Fill in the Blanks

How will I know
that I have
learned it?

I can find the area of a
large rectangle by dividing it
into two smaller rectangles
and then adding their areas
together.

Poll

How well do you understand how to use the distributive property of multiplication

• 1

  I still need a lot of practice

• 2

  I still need some more practice

• 3

  I understand it!

• 4

  I understand it and I could use to to solve all kinds of multiplication problems.