8A Unit 5 Test Corrections

Unit 5 Test Correction Session

Join with your name as it appears in Class

1. Check to see if you have like radicals.

   ex. 3√6 and 4√6

2. Add/subtract the coefficients.

   ex. 3√6 and 4√6

3. *Note: when you don't see a coefficient like √6, it's 1!

​Adding/Subtracting Radicals

Multiple Choice

Add $$19\sqrt[4]{5}+\sqrt[4]{5}$$

• $$19\sqrt[4]{5}$$

• $$20\sqrt[4]{5}$$

• $$24\sqrt[4]{5}$$

Multiple Choice

Subtract $$13\sqrt[5]{6}-7\sqrt[5]{6}$$

• $$6\sqrt[5]{6}$$

• $$20\sqrt[5]{6}$$

• $$6\sqrt[6]{12}$$

1. Make sure you have the same index ⁱ√

​2. Multiply coefficients (numbers in front of √)
3. Multiply radicands (numbers inside √)

​Multiplying/Dividing Radicals

1. Make sure you have the same index ⁱ√

​2. Multiply coefficients (numbers in front of √)
3. Multiply radicands (numbers inside √)

​Multiplying/Dividing Radicals

Multiple Choice

Simplify the following: $$4\sqrt[5]{2}\cdot9\sqrt[5]{6}$$

• $$13\sqrt[5]{8}$$

• $$36\sqrt[25]{12}$$

• $$36\sqrt[5]{12}$$

Multiple Choice

Simplify the following: $$18\sqrt[3]{10}\div9\sqrt[3]{2}$$

• $$9\sqrt[6]{12}$$

• $$2\sqrt[3]{5}$$

• $$9\sqrt[3]{8}$$

Finding Square and Cube Roots

--> Odd index ✅
--> Even index ❌

​

​What about Negatives?

​Here's why....

Even amount of negatives
(-) × (-) × (-) × (-) × (-) × (-) = (+) × (+) × (+) = (+)

2 negatives = A positive

-->There's no way you could take an even amount of negatives and it ever equal a negative.

Odd amount of negatives
(-)× (-) × (-) = (+) × (-) = (-)
--> It is possible to take an odd amount of negatives and it equal a negative.

Multiple Choice

What's $$\sqrt[]{25}$$ ?

• 5

• 12.5

• 625

Area of square = s²

So, s = √Area

**Has to be a square!

​

Area, Squares and Square Roots

Multiple Choice

What is the side length of a square if it's area is 64 square cm?

• 16 cm

• 4 cm

• 8 cm

​Volumes, Cubes and Cube Roots

Multiple Choice

What's the side length of a cube if it's volume is 64 cubic inches?

• 8 inches

• 4 inches

• 128 inches