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Solving Literal Equations Quizizz

Solving Literal Equations Quizizz

Assessment

Presentation

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Medium

•
CCSS
HSA.CED.A.4, 6.EE.C.9, HSA.REI.B.3

+1

Standards-aligned

Created by

Vanessa Wright-Greene

Used 11+ times

FREE Resource

9 Slides • 20 Questions

1

A Literal equation is easy if you know your basic operations and how to apply them to equations.

By now you know the basics,

but let us review.

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2

You have your basic one step equations where you use the opposite operator to solve for the variable.

Always maintain balance by doing the same operation to both sides.

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3

When you have more than one step to do, start by adding or subtracting any constants by themselves.

Then follow that with multiplying and dividing to isolate the variable.

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4

Sometimes you have a variable on both sides of the equation.

you can add and subtract variables just like constants. I suggest always starting with the smaller coefficient. notice 3 is smaller than 5, so we can subtract 3x from both sides. Then it becomes an easy two step equation. Try a few for practice.

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5

Multiple Choice

What should you do first?

5X - 3 = 2X + 4

1

Subtract 2 from both sides

2

Subtract 2X from both sides

3

Add 2X to both sides

4

Subtract 5X from both sides

6

Multiple Choice

What should you do first?

3X + 2 = -4X -5

1

Subtract 3X from both sides

2

Add 4X to both sides

3

Add 3X to both sides

4

Subtract 4X to both sides

7

Secret: You solve them the same way as other equations.

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8

A Literal equation contains at least two different variables.

Before you had one variable and you isolated it to get a numerical answer. In literal equations you still want to isolate a variable, just the answer will contain the other variables as well. Notice in the picture X and Z are isolated and all other variables and constants are on the other side of the equal sign.

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9

Here we have a literal equation already solved for H.

But what if we want to solve for A?

we can use the same opposite operations method we have been using to achieve this.

Our goal to get A by itself on one side of the equal sign and everything else on the other side.

on the next slide we will go over this step by step.

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10

Let us begin our process of getting A isolated.

Just as if this was 5=3x+4, we would start by -4 from both sides; we can

-r from both sides the same way. Then in the previous example we would divide by 3 from both sides; we can divide B from both sides. Now we know what A equals. Remember to only combine like terms. you will notice in literal equations, there are not many.

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11

Why do we even need this?

Some common literal equations involve converting temperature from celsius to fahrenheit or vice versa. There are also lots of literal equations in geometry. They will save you time.

Maybe you should try a few yourself.

Use paper and pencil if needed.

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12

Multiple Choice

Question image

Solve for A

ab=h\frac{a}{b}=h  

1

a=bha=bh  

2

a=bha=\frac{b}{h}  

3

a=hba=\frac{h}{b}  

13

Multiple Choice

Question image

Solve for C

cak+e=s\frac{ca}{k}+e=s  

1

c=aeskc=aesk  

2

c=kesac=\frac{kes}{a}  

3

c=k(s−e)ac=\frac{k\left(s-e\right)}{a}  

4

c=(s−e)akc=\frac{\left(s-e\right)}{ak}  

14

Multiple Choice

Solve for B.

A = BC + BD

1

B = (ACD)

2

B = (A - CD)

3

B=A/(C+D)

4

B=A/(CD)

15

Multiple Choice

Given ax−b=c, solve for x. Given\ ax-b=c,\ solve\ for\ x.\  

1

x = c+bax\ =\ \frac{c+b}{a}  

2

x = c−bax\ =\ \frac{c-b}{a}  

3

x = a+bcx\ =\ \frac{a+b}{c}  

4

x = c+abx\ =\ \frac{c+a}{b}  

16

Multiple Choice

Given xy + w = 9, solve for y.Given\ xy\ +\ w\ =\ 9,\ solve\ for\ y.  

1

y=9+wxy=\frac{9+w}{x}  

2

y=9−xwy=\frac{9-x}{w}  

3

y=9−wxy=\frac{9-w}{x}  

4

y=9+xwyy=\frac{9+x}{wy}  

17

Multiple Choice

Given d=rt, solve for r. Given\ d=rt,\ solve\ for\ r.\  

1

r=tdr=\frac{t}{d}  

2

t = drt\ =\ \frac{d}{r}  

3

d=rtd=\frac{r}{t}  

4

r=dtr=\frac{d}{t}  

18

Multiple Choice

Given mx+4y=3t, solve for x.Given\ mx+4y=3t,\ solve\ for\ x.  

1

x= 3t+4ymx=\ \frac{3t+4y}{m}  

2

x=3t−4ymx=\frac{3t-4y}{m}  

3

x=3m−4ytx=\frac{3m-4y}{t}  

4

x=3y+4tmx=\frac{3y+4t}{m}  

19

Multiple Choice

Given V=lwh, solve for l.Given\ V=lwh,\ solve\ for\ l.  

1

l=Vwhl=\frac{Vw}{h}  

2

l=Vwhl=\frac{V}{wh}  

3

l=Vhwl=\frac{Vh}{w}  

4

l=whVl=\frac{wh}{V}  

20

Multiple Choice

Given 5x−y=16, Solve for y.Given\ 5x-y=16,\ Solve\ for\ y.  

1

−y=5x+16-y=5x+16  

2

x=5y−16x=5y-16  

3

y=5x+16y=5x+16  

4

y=5x−16y=5x-16  

21

Multiple Choice

Given the equation y = mx + b.  What should we do first to solve for x?

1

Add

2

Multiply

3

Subtract

4

Divide

22

Multiple Choice

Solve: C=2πr, for rSolve:\ C=2\pi r,\ for\ r  



1

r=C2πr=\frac{C}{2\pi}  

2

r=C+2πr=C+2\pi  

3

r=C−2πr=C-2\pi  

4

r=2πCr=2\pi C  

23

Multiple Choice

Solve C=59(F−32), for F.Solve\ C=\frac{5}{9}\left(F-32\right),\ for\ F.  

1

F = 59C+32F\ =\ \frac{5}{9}C+32  

2

F = 59C−32F\ =\ \frac{5}{9}C-32  

3

F = 95C−32F\ =\ \frac{9}{5}C-32  

4

F = 95C+32F\ =\ \frac{9}{5}C+32  

24

Multiple Choice

Solve 3b=6v−3b, for b.Solve\ 3b=6v-3b,\ for\ b.  

1

6b−66b-6  

2

b−6b-6  

3

00  

4

66  

25

Multiple Choice

Solve ax−5=b, for a.Solve\ ax-5=b,\ for\ a.  

1

a=x(b+5)a=x\left(b+5\right)  

2

a=(b+5)xa=\frac{\left(b+5\right)}{x}  

3

a=(b−5)xa=\frac{\left(b-5\right)}{x}  

4

a=x(b−5)a=x\left(b-5\right)  

26

Multiple Choice

Given 8x+4y=16, solve for y.Given\ 8x+4y=16,\ solve\ for\ y.  

1

y=−2x+4y=-2x+4  

2

y=−8x+16y=-8x+16  

3

y=2x−4y=2x-4  

4

y=−8x+12y=-8x+12  

27

Multiple Choice

Solve y = mx + b for x.Solve\ y\ =\ mx\ +\ b\ for\ x.  

1

x=(y−b)mx=\frac{\left(y-b\right)}{m}  

2

x = y−bmx\ =\ y-\frac{b}{m}  

3

x=ym−bx=\frac{y}{m}-b  

28

Multiple Choice

Given 15x + 1 = y, solve for x.

1

x =y+115x\ =\frac{y+1}{15}  

2

x =y−151x\ =\frac{y-15}{1}  

3

x =y−115x\ =\frac{y-1}{15}  

4

x =y+151x\ =\frac{y+15}{1}  

29

Poll

How do you feel about solving equations?

I got this, it is easy.

I will feel better after I practice by finishing my homework.

I understand the basics

I need to ask you for more help

pattern-tertiary
A Literal equation is easy if you know your basic operations and how to apply them to equations.

By now you know the basics,

but let us review.

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