
Uniform Circular Motion
Presentation
•
Physics
•
12th Grade
•
Practice Problem
•
Medium
Standards-aligned
Michael Frankenhoff
Used 8+ times
FREE Resource
20 Slides • 19 Questions
1
Uniform Circular Motion
With Newton's Universal Law of Gravitation too!!!
2
Something going in a circle that has...
Constant radius
Constant speed
What is UCM?
3
The time to go around the circle once is called the period.
Symbol is T
Unit is seconds
It's the seconds per cycle/revolution etc.
Some basics
4
The inverse of this idea is frequency.
Symbol is f
Unit is 1/sec or a Hertz (Hz)
It's the cycles/revolutions per second.
Some basics
5
Remember...
1 revolution = 360 degrees = 2πrads
Some basics
6
Since v = x/t
If we go around once, x is the circumference and..
t is the period
giving....
v = C/T or
v = Dπ/T or 2πr/T
or 2πrf
Velocity
7
Velocity always points tangent to the circle.
Called tangential velocity
Acceleration always points towards the center
Called centripetal acceleration
Direction of vectors
8
Centripetal acceleration has a special equation.
a = v2/r
REMEMBER! Anything in UCM is accelerating even if its speed is constant because
It is changing direction and
Therefore changing velocity
Acceleration
9
Multiple Choice
A racing car is moving around the circular track of radius 300 meters shown above. At the instant
when the car's velocity is directed due east, its acceleration is directed due south and has a magnitude of 3 meters per second squared. When viewed from above, the car is moving
clockwise at 30 m/s
clockwise at 10 m/ s
counterclockwise at 30 m/ s
counterclockwise at 10 m/s
with constant velocity
10
Multiple Choice
A child has a toy tied to the end of a string and whirls the toy at constant speed in a horizontal
circular path of radius R. The toy completes each revolution of its motion in a time period T. What is
the magnitude of the acceleration of the toy?
Zero
T24π2R
T2πR
g
2πg
11
Multiple Choice
A figure of a dancer on a music box moves counterclockwise at constant speed around the path shown above. The path is such that the lengths of its segments, PQ, QR, RS, and SP, are equal. Arcs QR and SP are semicircles. Which of the following best represents the magnitude of the dancer's acceleration as a function of time t during one trip around the path, beginning at point P ?
12
Multiple Choice
Inside a washing machine, the radius of the cylinder where the clothes sit is 0.50 m. In one of its
settings the machine spins the cylinder at 2.0 revolutions per second. What is the acceleration of an
item of clothing?
0.080 m/s/s
1.6 m/s/s
8.0 m/s/s
79 m/s/s
13
To accelerate something towards the center of the circle...
There must be a net force towards the center of the circle.
Called centripetal force
Since ΣF = maC
FC = mv2/r
Force
14
Multiple Choice
An automobile moves at constant speed down one hill and up another hill along the smoothly curved
surface shown above. Which of the following diagrams best represents the directions of the velocity
and the acceleration of the automobile at the instant that it is at the lowest position. as shown?
15
Multiple Choice
An object moves at a constant speed in a circular path. Which of the following statements is/are true?
I. The velocity is constant
II. The centripetal acceleration is constant.
III. The net force on the object is zero.
I only
II only
III only
I and II
only
II and III
only
16
Multiple Select
A child whirls a ball at the end of a rope, in a uniform circular motion. Which of the following statements is true? Select two answers.
The speed of the ball is constant
The velocity is of the ball is constant
The magnitude of the ball's acceleration is constant
The net force on the ball is directed radially outwards
17
Multiple Choice
A ball attached to a string is whirled around in a horizontal circle having a radius r. If the radius of the circle is changed to 4r and the same centripetal force is applied by the string, the new speed of the ball is which of the following?
One-quarter the original speed
One-half the original speed
The same as the original speed
Twice the original speed
Four times the original speed
18
Multiple Choice
A car with speed v and an identical car with speed 2v both travel the same circular section of an
unbanked road. If the frictional force required to keep the faster car on the road without skidding is
F, then the frictional force required to keep the slower car on the road without skidding is
4F
2F
F
1/2 F
1/4 F
19
We will use the FBD to set up the 2nd Law with these rules.
Count as + any force that points towards the center.
Count as negative any force that points away from the center.
Ignore any forces that point tangent to the circle
Rules for Free Body Diagrams in UCM
20
Never never never label Fc on a FBD!!!!!!
Also the bigger force is ALWAYS the one pointing towards the center.
That's why it's going in a circle in the first place!
Rules for Free Body Diagrams in UCM
21
At the top both Fg and T point towards the center so...
Fg + T = mv2/r
At the bottom, T points towards the center and Fg away so..
T - Fg = mv2/r
Ex 1: Bucket swung in a vertical circle.
22
Multiple Choice
An object weighing 4 newtons swings on the end of a string as a simple pendulum. At the bottom of
the swing, the tension in the string is 6 newtons. What is the magnitude of the centripetal
acceleration of the object at the bottom of the swing?
0
0.5 g
g
1.5 g
2.5 g
23
Multiple Choice
A 4.0 kg mass is attached to one end of a rope 2 m long. If the mass is swung in a vertical circle from the free end of the rope, what is the tension in the rope when the mass is at its highest point if it is moving with a speed of 5 m/s?
5 N
10 N
40 N
90 N
24
Ex 1: Bucket swung in a vertical circle.
25
Multiple Select
A ball attached to a light string swings in a counterclockwise vertical circle, as shown above. Which
of the following arrows represent one of the forces exerted on the ball at the moment it passes
through point P ? Select two answers.
26
Ex 2: Roller coaster
27
Multiple Choice
A 100 kg cart goes around the inside of a vertical loop of a roller coaster. The radius of the loop is 3
m and the cart moves at a speed of 6 m/s at the top. The force exerted by the track on the cart at the top of the loop is
200 N
800 N
1000 N
1200 N
2200
28
Multiple Choice
A cart of mass is moving with speed on a smooth track when it encounters a vertical loop of radius as shown above. The cart moves along the inside of the entire loop without leaving the track. All frictional forces are negligible.
Which of the following must be true for the cart to remain on the track when it is at point ?
The net force exerted on the cart must be less than the force that the track exerts on the cart.
The net force exerted on the cart must be equal to or greater than the weight of the cart.
The track must exert an upward force on the cart to prevent it from falling.
The track must exert a force on the cart that is equal to the weight of the cart.
29
Ex 3: Car "hill hoppin'
30
Multiple Choice
The figures show a cart moving over the top of a hill (Case 1), moving at the bottom of a dip (Case 2), and moving at the top of a vertical loop (Case 3). In each case, the normal force acting on the car is N and the weight of the car is W. In which case is it
A) always true that N > W,
B) and in which case is it always true that W > N ?
A) Case 1
B) Case 3
A) Case 2
B) Case 1
A) Case 2
B) Case 3
A) Case 3
B) Case 1
31
Ex 4: Car turning on road
32
Multiple Choice
A horizontal disk rotates at a constant angular speed ω. As viewed from above, a coin of mass m on the disk moves counterclockwise in a circle of radius R as shown. Which of the following vectors best represents the direction of the frictional force
exerted on the coin by the disk when the coin is at the position shown?
33
Multiple Choice
A horizontal disk rotates at a constant angular speed ω. As viewed from above, a coin of mass m on the disk moves counterclockwise in a circle of radius R as shown. Which of the following expressions correctly represents the minimum coefficient of
static friction required to prevent the coin from sliding on the disk?
Rω2/g
ω2/Rg
Rω2/mg
mRω2
34
Ex 5: Person on the Gravitron
35
Tx points towards the center.
Ty and Fg are tangent so ignore.
Tx = Tsinθ = mv2/r
But remember Ty = Fg
So Tcosθ = mg and T = mg/cosθ
Subbing gives mgtanθ = mv2/r
Be careful, they could use the other angle
Ex 6: Bucket swung in horizontal circle, dipping slightly
36
They could just pretend the object does not dip.
In that case all of T points towards center
So just plain ol' T is the centripetal force.
Ex 6b: Bucket swung in horizontal circle, not dipping
37
Multiple Choice
A child has a toy tied to the end of a string and whirls the toy at constant speed in a horizontal circular path of radius R. The toy completes each revolution of its motion in a time period T. What is the magnitude of the acceleration of the toy?
Zero
4π2R / T2
πR / T2
g
2πg
38
We did a lab with an idealized set up like the picture to the right.
The tension is still the Fc but..
In this case the tension is also equal to the weight of the hanging mass, M.
So we can say Mg = mv2/r
Ex 6b: Cont.
39
Multiple Choice
A student has one end of a light string attached to an object of mass m, and the other end of the string is passed through a tube and attached to an object of mass M. The student swings mass m in a horizontal circle while mass M remains at a constant height. The period is T. Which of the following represents an equation to experimentally determine the gravitational field strength of Earth?
g = 4π²m₀L / MT²
g = 4π²ML / m₀T²
g = 4π²m₀ / MLT²
g = m₀L / 4π²MT²
Uniform Circular Motion
With Newton's Universal Law of Gravitation too!!!
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