Introduction to pH and pOH

Categorize

Options (10)

sour taste

bitter taste

pH = 8.2

pH = 1.8

turns blue litmus paper red

turns red litmus paper blue

slippery

increase hydroxide ions

increase hydrogen ions

pH = 5.4

Organize these options into the right categories.

Acid

Base

Multiple Choice

What is pH based on?

• The pOH.

• The dissociation of water.

• The concentration of hydroxide ions.

• The formation of water.

Multiple Select

Which of the following is equivalent to pH when water dissociates?

• The pOH.

• 7

• 14

• $$\left[H^+\right]$$

• $$\left[OH^-\right]$$

Multiple Choice

What equation will be used to solve the following problem?

What is the pH of solution with [H⁺] of 3.3 x 10^–9 M?

• $$pH\ =\ -\log\left[H^+\right]$$

• $$pOH\ =\ -\log\left[OH^-\right]$$

• $$\left[H^+\right]=10^{-pH}\$$

• $$\left[OH^-\right]=10^{-pOH}\$$

• $$pH\ +\ pOH\ =14$$

Multiple Choice

What equation will be used to solve the following problem?

What is the [H⁺] for a solution with a pH of 12.05?

• $$pH\ =\ -\log\left[H^+\right]$$

• $$pOH\ =\ -\log\left[OH^-\right]$$

• $$\left[H^+\right]=10^{-pH}\$$

• $$\left[OH^-\right]=10^{-pOH}\$$

• $$pH\ +\ pOH\ =14$$

Multiple Choice

What equation will be used to solve the following problem?

What is the pOH of solution with [OH^–] = 0.003 M?

• $$pH\ =\ -\log\left[H^+\right]$$

• $$pOH\ =\ -\log\left[OH^-\right]$$

• $$\left[H^+\right]=10^{-pH}\$$

• $$\left[OH^-\right]=10^{-pOH}\$$

• $$pH\ +\ pOH\ =14$$

Multiple Choice

What equation will be used to solve the following problem?

What is the [OH^–] of a solution with a pOH of 4.90?

• $$pH\ =\ -\log\left[H^+\right]$$

• $$pOH\ =\ -\log\left[OH^-\right]$$

• $$\left[H^+\right]=10^{-pH}\$$

• $$\left[OH^-\right]=10^{-pOH}\$$

• $$pH\ +\ pOH\ =14$$

Multiple Choice

What equation will be used to solve the following problem?

What is the pH of a sodium hydroxide solution with a pOH of 2.11?

• $$pH\ =\ -\log\left[H^+\right]$$

• $$pOH\ =\ -\log\left[OH^-\right]$$

• $$\left[H^+\right]=10^{-pH}\$$

• $$\left[OH^-\right]=10^{-pOH}\$$

• $$pH\ +\ pOH\ =14$$

Multiple Choice

What equation will be used to solve the following problem?

What is the pOH of a solution of a hydrochloric acid with a concentration of 0.0371 M?

(Hint: What does HCl produce when placed in water?)

• $$pH\ =\ -\log\left[H^+\right]$$

• $$pOH\ =\ -\log\left[OH^-\right]$$

• $$\left[H^+\right]=10^{-pH}\$$

• $$\left[OH^-\right]=10^{-pOH}\$$

• $$pH\ +\ pOH\ =14$$