
Electric Motor
Presentation
•
Physics
•
12th Grade
•
Practice Problem
•
Easy
Risdiyanto Risdi
Used 3+ times
FREE Resource
7 Slides • 10 Questions
1
Open Ended
Tulis Nama Lengkap dan Kelas
2
Open Ended
Discuss with your partner!
What do the tools in the picture have in common?
(apa kesamaan alat-alat dalam gambar)
3
The tools mentioned earlier all have electric motors. An electric motor helps convert electrical energy into mechanical energy. It is based on the principles of electromagnetism.
What is electric motor?
4
Construction of an electric motor
5
Match
Match the following
Komponen X dan Y
Komponen P dan Q
Sumber medan magnet
Sumber arus listrik
Kumparan berputar
Sikat penghubung arus & cincin berputar
Cincin berputar
Sumber medan magnet
Sumber arus listrik
Kumparan berputar
Sikat penghubung arus & cincin berputar
Cincin berputar
6
It has a rectangular coil of wire ABCD.
It has got a strong horseshoe magnet. The coil ABCD is placed perpendicular to this magnet.
The ends of the coil ABCD are connected to split rings P and Q. These split rings play the role of the commutator. It helps reverse the direction of the current flow.
The inners part of the split rings is insulated. It is attached to the axle. The axle is free to rotate.
The external side of the conducting edges of the split rings is connected with the stationary brushes. These brushes X and Y are connected with the battery. This completes the circuit.
Replace this
7
Open Ended
Tuliskan secara singkat dan jelas hal-hal yang dipahami dari slide sebelum ini!
8
Multiple Choice
Ke mana arah gaya magnet pada kawat AB?
atas
bawah
kanan
kiri
9
Multiple Choice
Ke mana arah gaya magnet pada kawat CD?
atas
bawah
kanan
kiri
10
11
Open Ended
Tuliskan secara singkat dan jelas hal-hal yang dipahami dari slide sebelum ini!
12
Bagaimana menghitung momen gaya pada kumparan?
13
Multiple Choice
Rumus dasar menghitung momen gaya (M) adalah ...
M = Fr
M = F r cos q
M = F r sin q
M = F r / sinq
M = F r / cosq
14
Rumus momen gaya pada kumparan?
15
Multiple Choice
Momen gaya pada kumparan dengan N lilitan, luas A, dialiri arus i, dan terletak dalam medan magnet B yang membentuk sudut q terhadap normal bidang kumparan adalah ...
M = NABi cosq
M = NABi sinq
M = NABi tanq
M = NABi / cosq
M = NABi / sinq
16
Multiple Choice
4,8 x 10^-3
9,6 x 10^-3
4,8 x 10^-5
9,6 x 10^-5
9,6 x 10^-6
17
Keep working hard and stay humble!
Congratulations for finishing the lesson!
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