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MP2 Lesson 15 Solving Square Root Equations

MP2 Lesson 15 Solving Square Root Equations

Assessment

Presentation

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Medium

•
CCSS
6.NS.B.3, HSA.REI.A.2

Standards-aligned

Created by

Anastasia Avila

Used 7+ times

FREE Resource

5 Slides • 6 Questions

1

Lesson 15 Solving Square Root Equations

TEKS 2A.3D, 4F, 4G, 7H

We will solve square root equations algebraically and graphically.
I will summarize the process of solving square root equations and finding extraneous solutions.

2

Solving a Radical Equation

3

Let's look at two examples:

media
media

4

Open Ended

After viewing the algebraic methods of solving these equations, how might you use technology to find solutions?

5

Let's talk about Extraneous Solutions before graphing...

6

Let's try solving equations graphically

7

Multiple Choice

Solve: x=19\sqrt[]{x}=\frac{1}{9}

1

118\frac{1}{18}

2
0
3

181\frac{1}{81}

4

136\frac{1}{36}

8

Fill in the Blanks

Solve: 6x−5+10=3\sqrt[]{6x-5}+10=3

Type answer...

9

Multiple Choice

Solve: 2510x+6=12\frac{2}{5}\sqrt[]{10x+6}=12

1
89.4
2
75.1
3
50.2
4
24.5

10

Multiple Choice

Solve: x2+5=x+3\sqrt[]{x^2+5}=x+3

1

−53-\frac{5}{3}

2
3
3

−23-\frac{2}{3}

4

12\frac{1}{2}

11

Math Response

In a right circular cone with a slant height of 1 unit, the radius r of a cone is given by r=1πS+π4−12r=\frac{1}{\sqrt[]{\pi}}\sqrt[]{S+\frac{\pi}{4}}-\frac{1}{2} , where S is the surface area of the cone. Graph the model. Then find the surface area of a right circular cone with a slant height of 1 unit and a radius of 1/2 unit. Keep your answer in terms of pi.

Type answer here
Deg°
Rad
pattern-tertiary
Lesson 15 Solving Square Root Equations

TEKS 2A.3D, 4F, 4G, 7H

We will solve square root equations algebraically and graphically.
I will summarize the process of solving square root equations and finding extraneous solutions.

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