Glycolysis, Pyruvate Oxidation and the Citric Acid Cycle

Math Response

For each molecule of glucose, 38 molecules of ATP are produced in cellular respiration. These 38 molecules can then provide cells with 277 kcal of energy, which can then be used to undergo processes such as active transport, among others. 

Calculate the amount of energy present within 1 molecule of ATP. 

Type answer here

Correct Answer: 277\div38=7.29

Deg^°

Rad

Multiple Choice

We know that glucose is a reactant of cellular respiration, but what other reactant should we expect to see here?

• O₂

• CO₂

• H₂O

• ATP

Multiple Choice

What is the net amount of ATP molecules made during glycolysis?

• 1

• 2

• 3

• 4

Open Ended

Describe how the process of glycolysis breaks down glucose. (Hint: What are the Products & Reactants of this reaction? What is the role of NADH?)

Multiple Choice

Does oxygen play a role in Glycolysis?

• Yes

• No

Multiple Choice

Where does pyruvate oxidation and the Citric acid Cycle take place?

• ribosome

• mitochondrion

• nucleus

• DNA

Multiple Choice

How many times does each pyruvate molecule go through the Citric Acid Cycle?

• once

• twice

• three times

• a lady

Open Ended

Describe how pyruvate oxidation and the Krebs’ Cycle continues to break down pyruvate.

Multiple Choice

Does oxygen play a role in pyruvate oxidation and/or the Citric Acid Cycle?

• yes

• no

Open Ended

Put It All Together

1. If pyruvate oxidation and the Citric Acid Cycle were switched off, could a cell still produce ATP? Justify your answer.

2. What about if glycolysis were switched off instead? Could a cell still produce ATP? Again, justify your answer.