
Trig Identity
Presentation
•
Mathematics
•
12th Grade
•
Hard
James Gonzalez
FREE Resource
11 Slides • 40 Questions
1
Trig Identities
+ Reciprocal
+ Quotient
2
Trig Identities
+ Pythagorean
+ Addition/Subtraction
3
Reciprocal Identities
Understand and be ready to apply the reciprocal properties including sine, cosine, tangent, cosecant, secant, and cotegent with numerator is 1
Be aware of the relationship between sine and cosecant, between cosine and secant, and between tangent and cotangent
4
Pythagorean Identities
Derive the Pythagorean identities from the unit circle definition of sine and cosine.
Be aware of the relationship between sine and cosecant, between cosine and secant, and between tangent and cotangent
Verify trigonometric identities using Pythagorean relationships.
Solve real-world problems involving right triangles and periodic phenomena by employing Pythagorean identities.
5
6
7
Multiple Choice
reciprocal of cos(θ) is?
sin(θ)
csc(θ)
sec(θ)
cot(θ)
tan(θ)
8
Multiple Select
sin2θ=
csc2θ1
1−cos2θ
1−sin2θ
sec2θ1
9
Multiple Choice
reciprocal of csc(θ) is?
sin(θ)
cos(θ)
sec(θ)
cot(θ)
tan(θ)
10
Multiple Select
cos2θ=
csc2θ1
1−cos2θ
1−sin2θ
sec2θ1
11
Multiple Choice
reciprocal of cot(θ) is?
sin(θ)
csc(θ)
sec(θ)
sin(θ)
tan(θ)
12
Multiple Select
cot2θ=
tan2θ1
csc2θ −1
sin2θ−1
cos2θsin2θ
sin2θcos2θ
13
Multiple Choice
reciprocal of sec(θ) is?
cos(θ)
csc(θ)
sin(θ)
tan(θ)
cot(θ)
14
Multiple Select
tan2θ=
cot2θ1
sec2θ −1
sin2θ−1
cos2θsin2θ
sin2θcos2θ
15
Multiple Choice
reciprocal of sin(θ) is?
cos(θ)
csc(θ)
sec(θ)
tan(θ)
cot(θ)
16
Multiple Select
sec2θ=
sin2θ1
cos2θ1
1+tan2θ
1+cot2θ
17
Multiple Choice
reciprocal of tan(θ) is?
cos(θ)
csc(θ)
sec(θ)
sin(θ)
cot(θ)
18
Multiple Select
csc2θ=
sin2θ1
cos2θ1
1+tan2θ
1+cot2θ
19
Multiple Choice
Given cos(60⁰) = 1/2, evaluate sec(60⁰)=?
21
23
22
1
2
20
Multiple Select
1=
sec2θ−tan2θ
csc2θ−cot2θ
sin2θ +cos2θ
sin2θ−cot2θ
cos2θ−tan2θ
21
Multiple Choice
Given sin(30⁰) = 1/2, evaluate csc(30⁰)=?
21
23
22
1
2
22
Objectives
We will be able to expand a trig expression by applying the sum or difference identity of that trig function.
We will be able to condense the expanded form of the sum or difference identity.
We will be able to evaluate the sin, cos, or tan of unfamiliar angles using the sum of difference of familiar angles.
23
Multiple Choice
Given csc(60°)=323 , evaluate sin(60°)=?
21
23
22
1
2
24
A rule to split angle is that angle must be equal to the sum or difference of two angles of reference (30⁰, 60⁰, 90⁰, 180⁰, 270⁰, and 360⁰)
25
Multiple Choice
Given sec(30°)=323 , evaluate cos(30°)=?
21
23
22
1
2
26
Multiple Choice
According to the reference of angle rule, which of the followings is best equivalent to sin(105⁰)?
sin(45⁰+60⁰)
sin(180⁰-75⁰)
sin(150⁰+45⁰)
sin(15⁰+90⁰)
27
Multiple Choice
Given tan(30°)=33 , evaluate cot(30°)=?
0
33
3
1
undefined
28
Multiple Select
According to the reference of angle rule, which of the followings is best equivalent to cos(150⁰)?
cos(75⁰+75⁰)
cos(180⁰-30⁰)
cos(100⁰+50⁰)
cos(60⁰+90⁰)
29
Multiple Choice
Given cot(60°)=33 , evaluate tan(60°)=?
0
33
3
1
undefined
30
Multiple Select
According to the reference of angle rule, which of the followings is best equivalent to tan(300⁰)?
cos(270⁰+30⁰)
cos(180⁰-120⁰)
cos(90⁰+210⁰)
cos(360⁰-60⁰)
31
Quotient Identities
Understand and be ready to apply the quotient properties including tangent and cotegent relationship with sine and cosine
Be aware of tangent and cotangent have both reciprocal and quotient properties
32
Sum and Difference Identities
33
34
Categorize
sinAcosB+cosAsinB
sinAcosB−cosAsinB
cosAcosB −sinAsinB
cosAcosB+sinAsinB
Match the sum and difference identities for sine and cosine
35
Multiple Select
Which are equivalent to tan(θ)?
1/cot(θ)
sin(θ)/cos(θ)
cos(θ)/sin(θ)
1/tan(θ)
csc(θ)/sec(θ)
36
Multiple Select
tan(A+B)=
(1−tanAtanB)tan(A)+tan(B)
(1+tanAtanB)tan(A)−tan(B)
cos(A+B)sin(A+B)
cos(A−B)sin(A−B)
37
Multiple Select
Which are equivalent to cot(θ)?
1/cot(θ)
sin(θ)/cos(θ)
cos(θ)/sin(θ)
1/tan(θ)
csc(θ)/sec(θ)
38
Multiple Select
tan(A−B)=
(1−tanAtanB)tan(A)+tan(B)
(1+tanAtanB)tan(A)−tan(B)
cos(A−B)sin(A−B)
cos(A−B)sin(A−B)
39
Multiple Choice
According to the reciprocal identity, which proof of the followings is sinx = 1/cscx
sinx=1×1(sinx)
=sinx
1/cscx=1/(1/sinx)
=1/cscx
sinx =1÷sinx1
= 1÷cscx= cscx1
sinx=sinx÷(sinxsinx) = sinx÷(sinx×cscx) =cscx
40
Multiple Choice
cos90ocos45o−sin90o sin45o is equivalent to
sin 45o
sin 135°
cos 135o
cos45o
41
Multiple Choice
According to the reciprocal identity, which proof of the followings is cosx =secx1
cosx=1×1(cosx)
=1÷cosx1
=1÷secx = secx1
1/secx=1/(1/cosx)
=1/secx
cosx =1×cosx1
= 1÷secx= secx1
cosx=cosx÷(cosxcosx) = cosx÷(cosx×secx) =secx
42
Multiple Choice
cos90ocos45o+sin90o sin45o is equivalent to
sin 45o
sin 135°
cos 135o
cos45o
43
Multiple Choice
According to the reciprocal identity, which proof of the followings is cotx =tanx1
cotx=1×1(cotx)
=1×cotx1
=tan
1/tanx=1÷tanx
=1÷(cosxsinx)
1×sinxcosx=cotx
cotx =1×cotx1
= 1÷cotx= cotx1
cotx=cotx÷(cotxcotx) = cotx÷(cotx(tanx)1) =tanx
44
Multiple Choice
sin90ocos45o+cos90o sin45o is equivalent to
sin 45o
sin 135°
cos 135o
cos45o
45
Multiple Choice
According to quotient identity we have tanx = sinx/cosx, tanx = 1/cotx, show that cotx = cosx/sinx.
True because
cotx=tanx1
1÷(cosxsinx) = sinxcosx
False because
tanx = cosxsinx, then
tanx1= sinxcosx
False because
cotx = 1÷tanx= cosxsinx
True because
sinxcosx=1×cosxsinx =tanx1=cotx
46
Multiple Choice
sin90ocos45o−cos90o sin45o is equivalent to
sin 45o
sin 135°
cos 135o
cos45o
47
Fill in the Blanks
48
Multiple Choice
Which of the followings is more acurate proof to determine cos(180⁰ + θ)?
sin(180⁰)cosθ + cos(180⁰)sinθ =
-sinθ
sin(180⁰)cosθ -cos(180⁰)sinθ =
sinθ
cos(180⁰)cosθ -sin(180⁰)sinθ =
-cosθ
cos(180⁰)cosθ + sin(180⁰)sinθ =
-cosθ
49
Fill in the Blanks
50
Multiple Choice
Which of the followings is more acurate proof to determine sin(180⁰ + θ)?
sin(180⁰)cosθ + cos(180⁰)sinθ =
-sinθ
sin(180⁰)cosθ -cos(180⁰)sinθ =
sinθ
cos(180⁰)cosθ -sin(180⁰)sinθ =
-cosθ
cos(180⁰)cosθ + sin(180⁰)sinθ =
-cosθ
51
Multiple Choice
Give sin(θ) = 0, cos(θ) = -1 Calculate exactvalue of sin(θ + φ)
sin(θ)cos(φ) + cos(θ)sin(φ)
= sin(φ)
sin(θ)cos(φ) + cos(θ)sin(φ)
= -sin(φ)
sin(θ)cos(φ) - cos(θ)sin(φ)
= sin(θ)
sin(θ)cos(φ) - cos(θ)sin(φ)
= -sin(θ)
Trig Identities
+ Reciprocal
+ Quotient
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