
Angles and Bisector
Presentation
•
Mathematics
•
8th - 10th Grade
•
Hard
Joseph Anderson
FREE Resource
9 Slides • 14 Questions
1
Angle Bisectors & Perpendicular Bisectors
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2
Angle Bisectors
3
Bisecting an angle means dividing it into two congruent angles.
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4
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5
Solution:
Each new angle measures 15°. Multiply by 2 to find the original, larger angle.
15° × 2 = 30°
So, the original angle measured 30°.
6
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7
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8
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9
Multiple Choice
The figure shows a triangle with one of its angle bisectors. Find x if m∠2 = 4x + 5 and m∠1 = 5x − 2.
x = 7
x = 3
x = -7
x = 1/3
10
Angle Bisector Theorem
The Angle Bisector Theorem states that a point is on the bisector of an angle if and only if it is in the interior of the angle and is equidistant from the sides of the angle.
Z is on the angle bisector of ∠WXY if and only if it is in the interior of ∠WXY and WZ
≅YZ
.
11
Example:
Look at the Diagram. Since m∠GHJ=m∠IHJ=66°,
HJ bisects ∠GHI.
Therefore, GJ≅IJ
by the Angle Bisector Theorem.
So, I=G=49.
12
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13
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14
Perpendicular Bisector Theorem
The Perpendicular Bisector Theorem
states that a point is on the perpendicular bisector of a segment if and only if it is equidistant from the endpoints of the segment.
B is on the perpendicular bisector of AC if and only if AB≅BC
.
15
Example
Since UV=VW=54, V is equidistant from the endpoints of UW. Therefore, V lies on the perpendicular bisector of UW by the Perpendicular Bisector Theorem.
Since V is on the perpendicular bisector of UW and ∠VXW is a right angle, VX is the perpendicular bisector of UW.
So, UX=WX=35 and UW=2(35)=70.
16
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17
Solution: Label the diagram
Since ∠TSU is a right angle and S=S=65, SU is the perpendicular bisector of TV.
Therefore, TU≅UV
by the Perpendicular Bisector Theorem.
So, U=T=98.
18
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19
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20
Multiple Choice
Can you use the perpendicular bisector theorem to solve for GH?
Yes.
No. We haven't been given enough information.
21
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22
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23
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Angle Bisectors & Perpendicular Bisectors
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