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Equations with Exponents

Equations with Exponents

Assessment

Presentation

Mathematics

11th Grade

Hard

Created by

Joseph Anderson

FREE Resource

5 Slides • 17 Questions

1

Exponents & Exponential Equations

When the bases are the same and when bases are not the same.

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Dr. Tom Giles

2

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3

4

Multiple Choice

3(3a1)=2433^{\left(-3a-1\right)}=243  



When looking at the equation above can 243 be expressed as base 3 to a power?

1

Yes

2

No

5

Multiple Choice

3(3a1)=2433^{\left(-3a-1\right)}=243  

3(3a1)=3?3^{\left(-3a-1\right)}=3^?  

What is the exponent we are looking for?

1

x

2

2

3

-5

4

5

6

Multiple Choice

3(3a1)=353^{\left(-3a-1\right)}=3^5  
What should we do next?

1

Take the logarithm of both sides.

2

Set the exponents equal to each other.

7

Multiple Choice

3(3a1)=353^{\left(-3a-1\right)}=3^5  
3a1=5-3a-1=5  
What is the value of  aa  ?

1

66  

2

2-2  

3

74\frac{7}{4}  

4

3-3  

8

Multiple Choice

Solve the equationSolve\ the\ equation  
5(2a3)=255^{\left(-2a-3\right)}=25  
a=?a=?  

1

52-\frac{5}{2}  

2

17-\frac{1}{7}  

3

158\frac{15}{8}  

4

32\frac{3}{2}  

9

Multiple Choice

4(x1)=64(2x2)4^{\left(x-1\right)}=64^{\left(2x-2\right)}  
Which is the correct way to rewrite the equation using like bases?

1

4(x1)=(42)(2x2)4^{\left(x-1\right)}=\left(4^2\right)^{\left(2x-2\right)}  

2

4(x1)=(43)(2x2)4^{\left(x-1\right)}=\left(4^3\right)^{\left(2x-2\right)}  

10

Multiple Choice

Which is the correct way to solve the equation?

1


4(x1)=(43)(2x2)4^{\left(x-1\right)}=\left(4^3\right)^{\left(2x-2\right)}


4(x1)=4(6x6)4^{\left(x-1\right)}=4^{\left(6x-6\right)}

x1=6x6x-1=6x-6

2

4(x1)=(43)(2x2)4^{\left(x-1\right)}=\left(4^3\right)^{\left(2x-2\right)}

4(x1)=4(6x2)4^{\left(x-1\right)}=4^{\left(6x-2\right)}

x1=6x2x-1=6x-2

11

Multiple Choice

4(x1)=(43)(2x2)4^{\left(x-1\right)}=\left(4^3\right)^{\left(2x-2\right)}  

4(x1)=4(6x6)4^{\left(x-1\right)}=4^{\left(6x-6\right)}  


x1=6x6x-1=6x-6  
What is the value of x?

1

4-4  

2

11  

3

33  

4

10-10  

12

Multiple Choice

64(2n+1)=16(2n+2)64^{\left(2n+1\right)}=16^{\left(2n+2\right)}  
What is the value of n?

1

87-\frac{8}{7}  

2

75\frac{7}{5}  

3

12\frac{1}{2}  

4

110\frac{1}{10}  

13

14

Multiple Choice

5x=185^x=18  
Can you get both sides of the equation with the same base?

1

Yes

2

No

15

Multiple Choice

5x=185^x=18  
Which is the correct way to proceed?

1

log 5x=18\log\ 5^x=18  

2

log 5x=log 18\log\ 5^x=\log\ 18  

16

Multiple Choice

5x=185^x=18  
log5x=log18\log5^x=\log18  
What should be the next step?

1

Divide both sides by log 5

2

Divide both sides by log 18

3

Use the Power Property of logarithms

17

Multiple Choice

5x=185^x=18  
log5x=log 18\log5^x=\log\ 18  
xlog5=log18x\log5=\log18  

xlog5log5=log18log5\frac{x\log5}{\log5}=\frac{\log18}{\log5}  
x=?

1

2.96932.9693  

2

1.79591.7959  

3

1.25531.2553  

18

Multiple Choice

17x=5617^x=56  
What is the value of x?

1

1.74821.7482  

2

4.02544.0254  

3

1.42081.4208  

19

20

Fill in the Blank

9(x+3)2=44.19^{\left(x+3\right)}-2=44.1  

Find the solution. (Nearest ten thousandths).

-
.

21

Fill in the Blank

6(b7)8.1=29.16^{\left(b-7\right)}-8.1=29.1  

Find the solution. (Nearest ten thousandths).

.

22

Open Ended

What is one or more things you would like to remember about today's lesson?

What is a question you still have and you need clarified?

Exponents & Exponential Equations

When the bases are the same and when bases are not the same.

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Dr. Tom Giles

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