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Perpendicular Bisector and Circumcenter

Perpendicular Bisector and Circumcenter

Assessment

Presentation

Mathematics

9th - 10th Grade

Hard

Created by

Joseph Anderson

FREE Resource

12 Slides • 5 Questions

1

Perpendicular Bisectors

Geometry Honors

Ms. Hogan

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2

Math Spoken Here!

Perpendicular Bisector: A segment, ray, line, or plane that is perpendicular to a segment at its midpoint.


Equidistant: A point is equidistant from two figures if it is the same distance from each figure.


Note that the red line is equidistant from the endpoints of c and is perpendicular to side c.


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3

Need to know...

In a plane:


If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.


If a point is equidistant from the endpoints of a segment then it is on the perpendicular bisector of the segment.

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4

Take Notice:

Did you notice that when the perpendicular bisector passes through the vertex point and the base, then the legs are congruent?


In an isosceles triangle a perpendicular bisector that passes through the base will always pass through the vertex point leaving two congruent legs.


Look closely at the image.

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5

Multiple Choice

Question image
Find HG
1
28
2
14
3
41
4
7

6

Multiple Choice

Question image
1

JM = 5

2

JM = 10

3

JM = 12

4

JM = 24

7

Multiple Select

Question image

Select every true statement below.

1

BC = 10 ft.

2

AD = 36 ft.

3

BE = 10 ft.

4

DE = 36 ft.

8

Take note:

The perpendicular bisector of a side of a triangle does not always pass through the opposite vertex.

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9

10

Math Spoken Here!

Concurrent: When three or more lines rays or segments intersect in the same point.


Point of Concurrency: The point of intersection of the lines, rays, or segments.

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11

Math Proven Here!

Given: Lines ℓ, m, and n are the perpendicular bisectors of AB , BC , and _ AC , respectively. P is the intersection of ℓ, m, and n. Prove: PA = PB = PC

​P is the intersection of ℓ, m, and n. Since P lies on the perpendicular bisector of AB , PA = PB by the Perpendicular Bisector Theorem. Similarly, P lies on the perpendicular bisector of BC , so PB = PC. Therefore, PA = PB = PC by the Transitive Property of Equality.

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12

An example of the use of concurrency of perpendicular bisectors.

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13

Math Spoken Here!

Circumcenter: The point of concurrency of the three perpendicular bisectors of a triangle.

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14

Circumcenter:

The circumcenter (call it P) is equidistant from the three vertices, so P is the center of a circle that passes through all three vertices.


As shown, the location of P depends on the type of triangle. The circle with center P is said to be circumscribed about the triangle.

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15

Multiple Choice

Question image
Point P is the circumcenter, which segment is equal to PB
1
DA
2
AC
3
PC
4
PF

16

Multiple Choice

Question image
Name the point of concurrency shown.
1
Circumcenter
2
Incenter
3
Supercenter
4
Neither

17

Great job!

More information and practice can be found in your HMH Textbook L8.1

Perpendicular Bisectors

Geometry Honors

Ms. Hogan

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