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Right Triangle Trigonometry: Missing Sides and Angles

Right Triangle Trigonometry: Missing Sides and Angles

Assessment

Presentation

Mathematics

9th - 12th Grade

Hard

Created by

Joseph Anderson

FREE Resource

4 Slides • 16 Questions

1

Right Triangle Trigonometry

GOAL: To apply what we know about trigonometry to degree applications.

2

Multiple Choice

If I know the lengths of TWO sides of a RIGHT triangle then I can find the length of the third side.

1

TRUE; using Pythagorean Theorem

2

False; you would need information on an angle or two.

3

Multiple Choice

Question image
Find the length of the missing side. 
1
17 cm
2
22 cm
3
15 cm
4
13 cm

4

Multiple Choice

Question image
Find the length of the missing side. 
1
20 in.
2
68 in.
3
16 in.
4
80 in.

5

media

This does not need to apply to ONLY the special right triangles. It can apply to ANY right triangle.

Recall:

SOHCAHTOA​

6

Multiple Select

Question image

Focus in on the 70o angle...which two sides are "identified" in the figure?

1

opposite

(an unknown)

2

hypotenuse

(4 units)

3

adjacent

(no marking)

4

None of these

7

Multiple Choice

Question image

So we should have found;

opposite side = ?

hypotenuse = 4

(remember...related to the 70o angle!!!) Which trig ratio uses these two sides?

1

sine (sin)

2

cosine (cos)

3

tangent (tan)

4

None of these

8

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​sin70o = ?/4

Check to be sure your calculator is in DEGREE MODE.

If you need help here - ask Mr Delgado

So - consider this;

9

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sin70o is about 0.9396926...

0.9396926...=?/4​

How do you solve for the ?​

10

Multiple Choice

Question image

0.9396926...=?40.9396926...=\frac{?}{4}  , to solve

1

multiply both sides by 4

2

divide both sides by 4

3

add 4 to both sides

4

subtract 4 from both sides

11

Multiple Choice

Question image

Since we need to multiply both sides by 4 given 0.9396926...=?40.9396926...=\frac{?}{4}  , the length of the side marked with a ? is __.

1

3.7588

4sin70°4\cdot\sin70\degree  

2

3.6

.94.9\cdot4  

3

0.2349

sin704\frac{\sin70}{4}  

4

-0.9848

sin704\sin70\cdot4  

12

Multiple Select

Question image

Let's consider angle B (25o). Which two sides do "b" and "8" represent?

1

Opposite

2

Adjacent

3

Hyptonuse

4

All of them

13

Multiple Choice

Question image

Let's focus on these two;

Opposite Side = "b"

Adjacent Side = "8"

(in relationship to angle B)

Which trig ratio uses these two sides?

1

sine (sin)

2

cosine (cos)

3

tangent (tan)

4

none of them

14

Multiple Choice

Question image

So now...which of the following equations would hold true?

1

tan(25°)=b8\tan\left(25\degree\right)=\frac{b}{8}  

2

tan(8°)=25b\tan\left(8\degree\right)=\frac{25}{b}  

3

tan(25°)=8b\tan\left(25\degree\right)=\frac{8}{b}  

4

tan(b°)=825\tan\left(b\degree\right)=\frac{8}{25}  

15

Multiple Choice

Question image

Which of the following best represents the length of side "b?"

1

3.73

2

177.88

3

17.16

4

17.74

16

Multiple Choice

Question image

Choose the correct set up to find the length of the side x.

1

sin(37°)=x14\sin\left(37\degree\right)=\frac{x}{14}  

2

cos(37°)=x14\cos\left(37\degree\right)=\frac{x}{14}  

3

tan(37°)=x14\tan\left(37\degree\right)=\frac{x}{14}  

4

None of these are correct

17

Multiple Choice

Question image

Find the value of x.

1

8.43

2

11.18

3

10.55 

4

None of these are correct

18

Multiple Choice

Question image

What is the correct set up for the problem to solve for side w?

1

sin(40°)=w28\sin\left(40\degree\right)=\frac{w}{28}  

2

cos(40°)=w28\cos\left(40\degree\right)=\frac{w}{28}  

3

tan(40°)=w28\tan\left(40\degree\right)=\frac{w}{28}  

4

sin(40°)=28w\sin\left(40\degree\right)=\frac{28}{w}  

19

Multiple Choice

Question image

What is the length of side "w?"

1

18.0 

2

21.4

3

23.5

4

43.56 

20

Multiple Choice

Question image

OK, go...Find the length of "x."

1
6.57 cm
2
7 cm
3
7.44 cm
4
26.33 cm

Right Triangle Trigonometry

GOAL: To apply what we know about trigonometry to degree applications.

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