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Systems Substitution Iready

Systems Substitution Iready

Assessment

Presentation

Mathematics

8th - 12th Grade

Hard

Created by

Joseph Anderson

FREE Resource

3 Slides • 6 Questions

1

Solving Systems by Substitution

Another way to find the solution between two equations.

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2

Steps:

  • isolate one of the equations (get into x= or y=)

  • Substitute - plug that equation into the other equation

  • Solve for the remaining variable

  • Take that answer and plug into the 1st equation

  • Solve for the remaining variable

3

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4

Multiple Choice

One equation is already isolated. Which choice shows the correct substitution?

2x3y=12x−3y=−1    y=x1\ y=x−1  

1

2x3(x1)=12x-3(x-1)=-1  

2

2x3y=x12x-3y=x-1

3

2(x1)3y=12(x-1)-3y=-1  

5

Multiple Choice

2x3(x1)=12x-3(x-1)=-1  

Solve for x

1

x = - 4

2

x = - 2

3

x = 2

4

x = 4

6

Multiple Choice

2x3y=12x−3y=−1   y=x1y=x-1  

Plug in x = 4 . 

You can plug into either one (but I like the one that is already in y=...)   

1

y = 3

2

y = - 3

3

y = 5

4

y = - 5

7

Fill in the Blank

Since x=4 and y=3, the solution is ___

Remember when you write and ordered pair, to use ( , )

**don't put any spaces**

8

Multiple Choice

What kind of solution, is (4,3)?

1

No Solution

2

Many Solution

3

One Solution

9

Multiple Choice

What does a One Solution system look like?

1

parallel lines

2

intersecting lines

3

two lines that are the same

Solving Systems by Substitution

Another way to find the solution between two equations.

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