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Zero Product Property Polynomials

Zero Product Property Polynomials

Assessment

Presentation

Mathematics

11th Grade

Hard

Created by

Joseph Anderson

FREE Resource

3 Slides • 14 Questions

1

Solving Polynomial Functions:
The Zero Product Property

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2

Multiple Choice

Factor:

x2 + 11x + 24

1

(x + 6)(x + 4)

2

(x + 12)(x + 2)

3

(x - 8)(x - 3)

4

(x + 8)(x + 3)

3

Multiple Choice

What are the factors of 3x2-17x+10
1
(x-5)(3x-2)
2
(x+5)(3x+2)
3
(3x-5)(x-2)
4
(x+5)(3x-2)

4

Multiple Choice

Find the factors of 5x2+20x+20
1
5(x+2)(x+2)
2
5(x-2)(x-2)
3
5(x+2)(x-2)
4
(5x+2)(x+2)

5

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6

Zero Product Property

Steps:
1. Make sure polynomial is in standard form=0
2. Factor the polynomial completely.
3. Set each factor=0 and solve.
4. Write your answers as a solution set.
Here is a video

7

Multiple Choice

Solve for the values of x:
(x - 3)(x + 6) = 0
1
{ -3, -6 }
2
{ 3, -6 }
3
{ -3, -6 }
4
{ 3, 6 }

8

Multiple Choice

Factor Completely: 
3x2 + 18x +15
Hint: Factor GCF first.
1
3(x2 + 6x + 5)
2
(x + 5)(x + 1)
3
3(x + 5)(x + 1)
4
Prime

9

Multiple Choice

Solve:

3x2 + 18x +15 = 0

Hint: Factor GCF first.

1

x = 3, 2

2

x = 5, 1

3

x = -5, -1

4

x = -3, -2

10

Multiple Choice

Factor Completely:

x2 - 49

1
(x - 7)(x - 7)
2
(x - 49)(x + 1)
3
(x - 14)(x + 14)
4
(x - 7)(x + 7)

11

Multiple Choice

Solve:

x2 - 49 = 0

1

x = -7, x = 7

2

x = -7

3

x = 7

4

x = -7, x = 1

12

Multiple Choice

Solve: (5x+4)(x2)=0\left(5x+4\right)\left(x-2\right)=0

1
x = -4/5, x = 2
2

x = 2, x = -4

3
x = -2, x = 4
4
x = 0, x = 2

13

Multiple Choice

Solve:  2x215=x2x^2-15=x  

Remember to rearrange the equation into standard form=0.

1

x=52x=-\frac{5}{2}  and  x=3x=3  

2

x=52x=\frac{5}{2}  and  x=3x=-3  

3

x=52x=\frac{5}{2}  and  x=3x=3  

4

x=52x=-\frac{5}{2}  and  x=3x=-3  

14

Multiple Choice

Solve:

k2 - 2k = 24

1

k = -4, 6

2

k = -4, -6

3

k = -6, 1

4

k = 4, -6

15

Multiple Choice

Solve: x25x+6=0x^2-5x+6=0

1
x = 2, x = 3
2
x = 0, x = 5
3
x = -2, x = -3
4
x = 1, x = 4

16

Multiple Choice

Solve: 4k28k3=35k2-4k^2-8k-3=-3-5k^2

1
k = 2
2
k = 4
3
k = 0 or k = 8
4
k = -1

17

Multiple Choice

Solve: 3b34b227b=363b^3-4b^2-27b=-36

1

b = 3, 4/3

2

b = -3, -9

3

b = 3, 9

4

b = 3, -3, 4/3

Solving Polynomial Functions:
The Zero Product Property

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