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Specific Heat Equation

Specific Heat Equation

Assessment

Presentation

Chemistry

9th - 12th Grade

Practice Problem

Hard

Created by

Jeffrey Oates

Used 2+ times

FREE Resource

6 Slides • 30 Questions

1

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2

Multiple Choice

Identify the variable for the following unit:

grams

1

Q

2

m

3

c

4

T

3

Multiple Choice

Identify the variable for the following unit:

joules per gram per degree Celsius

1

Q

2

m

3

c

4

T

4

Multiple Choice

Identify the variable for the following unit:

Celsius

1

Q

2

m

3

c

4

T

5

Multiple Choice

Identify the variable for the following unit:

joules

1

Q

2

m

3

c

4

T

6

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7

Multiple Choice

What variable is the number 700.?

How much energy is needed to increase the temperature of 700. g of water from 22°C to 98°C?  The specific heat of water is 4.18 J/g°C.

1

Q

2

m

3

c

4

T

8

Multiple Choice

What variable is the number 4.18?

How much energy is needed to increase the temperature of 700. g of water from 22°C to 98°C?  The specific heat of water is 4.18 J/g°C.

1

Q

2

m

3

c

4

T

9

Multiple Choice

What is the change in temperature?

ΔT = Tfinal - Tinital

How much energy is needed to increase the temperature of 700. g of water from 22°C to 98°C?  The specific heat of water is 4.18 J/g°C.

1

-76°C

2

76°C

3

120°C

4

88°C

10

Multiple Choice

What variable is the goal?

How much energy is needed to increase the temperature of 700. g of water from 22°C to 98°C?  The specific heat of water is 4.18 J/g°C.

1

Q

2

m

3

c

4

T

11

Multiple Choice

Select the derived equation to solve for the goal?

How much energy is needed to increase the temperature of 700. g of water from 22°C to 98°C?  The specific heat of water is 4.18 J/g°C.

1

Q=mcΔTQ=mc\Delta T

2

ΔT=Qmc\Delta T=\frac{Q}{mc}

3

m=QcΔTm=\frac{Q}{c\Delta T}

4

c=QmΔTc=\frac{Q}{m\Delta T}

12

Multiple Choice

Solve:

How much energy is needed to increase the temperature of 700. g of water from 22°C to 98°C?  The specific heat of water is 4.18 J/g°C.

1

2 220 000 J

2

2 220 J

3

22 200 J

4

222 000 J

13

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14

Multiple Choice

What variable is the number 1240?

An unknown mass of silver is heated with 1240 J of energy and increases in temperature by 50°C, what is the mass of the silver? The specific heat of silver is 0.24 J/g°C

1

Q

2

m

3

c

4

T

15

Multiple Choice

What variable is the number 0.24?

An unknown mass of silver is heated with 1240 J of energy and increases in temperature by 50°C, what is the mass of the silver? The specific heat of silver is 0.24 J/g°C

1

Q

2

m

3

c

4

T

16

Multiple Choice

What variable is the number 50?

An unknown mass of silver is heated with 1240 J of energy and increases in temperature by 50°C, what is the mass of the silver? The specific heat of silver is 0.24 J/g°C

1

ΔT

2

Tfinal

3

Tinitial

4

Q

17

Multiple Choice

What variable is the goal?

An unknown mass of silver is heated with 1240 J of energy and increases in temperature by 50°C, what is the mass of the silver? The specific heat of silver is 0.24 J/g°C

1

Q

2

m

3

c

4

T

18

Multiple Choice

Select the derived equation to solve for the goal?

An unknown mass of silver is heated with 1240 J of energy and increases in temperature by 50°C, what is the mass of the silver? The specific heat of silver is 0.24 J/g°C

1

Q=mcΔTQ=mc\Delta T

2

ΔT=Qmc\Delta T=\frac{Q}{mc}

3

m=QcΔTm=\frac{Q}{c\Delta T}

4

c=QmΔTc=\frac{Q}{m\Delta T}

19

Multiple Choice

Solve:

An unknown mass of silver is heated with 1240 J of energy and increases in temperature by 50°C, what is the mass of the silver? The specific heat of silver is 0.24 J/g°C

1

15 000 g Ag

2

300 000 g Ag

3

6 g Ag

4

100 g Ag

20

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21

Multiple Choice

What variable is the number 6500?

A substance with unknown specific heat and mass of 250 grams is heated with 6500 J of energy. If the initial temperature was 22°C and the final was 72°C. What is the specific heat of the substance?

1

Q

2

m

3

c

4

T

22

Multiple Choice

What variable is the number 250?

A substance with unknown specific heat and mass of 250 grams is heated with 6500 J of energy. If the initial temperature was 22°C and the final was 72°C. What is the specific heat of the substance?

1

Q

2

m

3

c

4

T

23

Multiple Choice

What variable is the number 72?

A substance with unknown specific heat and mass of 250 grams is heated with 6500 J of energy. If the initial temperature was 22°C and the final was 72°C. What is the specific heat of the substance?

1

Q

2

Tfinal

3

Tinitial

4

ΔT

24

Multiple Choice

What variable is the number 22?

A substance with unknown specific heat and mass of 250 grams is heated with 6500 J of energy. If the initial temperature was 22°C and the final was 72°C. What is the specific heat of the substance?

1

Q

2

Tfinal

3

Tinitial

4

ΔT

25

Multiple Choice

What variable is the goal?

A substance with unknown specific heat and mass of 250 grams is heated with 6500 J of energy. If the initial temperature was 22°C and the final was 72°C. What is the specific heat of the substance?

1

Q

2

m

3

c

4

T

26

Multiple Choice

Select the derived equation to solve for the goal?

A substance with unknown specific heat and mass of 250 grams is heated with 6500 J of energy. If the initial temperature was 22°C and the final was 72°C. What is the specific heat of the substance?

1

Q=mcΔTQ=mc\Delta T

2

c=ΔTmQc=\frac{\Delta T}{mQ}

3

c=mQΔTc=\frac{mQ}{\Delta T}

4

c=QmΔTc=\frac{Q}{m\Delta T}

27

Multiple Choice

Solve:

A substance with unknown specific heat and mass of 250 grams is heated with 6500 J of energy. If the initial temperature was 22°C and the final was 72°C. What is the specific heat of the substance?

1

0.52 J/g°C

2

0.52 cal/g°C

3

0.27 J/g°C

4

0.27 cal/g°C

28

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29

Multiple Choice

What variable is the number 53?

An aqueous reaction releases 2000 J of energy into 53 grams of water at 22°C. What is the final temperature?

Assume the specific heat of solution is 4.18 J/g°C.

1

Q

2

m

3

c

4

T

30

Multiple Choice

What variable is the number 2000?

An aqueous reaction releases 2000 J of energy into 53 grams of water at 22°C. What is the final temperature?

Assume the specific heat of solution is 4.18 J/g°C.

1

Q

2

m

3

c

4

T

31

Multiple Choice

What variable is the number 4.18?

An aqueous reaction releases 2000 J of energy into 53 grams of water at 22°C. What is the final temperature?

Assume the specific heat of solution is 4.18 J/g°C.

1

Q

2

m

3

c

4

T

32

Multiple Choice

What variable is the number 22?

An aqueous reaction releases 2000 J of energy into 53 grams of water at 22°C. What is the final temperature?

Assume the specific heat of solution is 4.18 J/g°C.

1

Q

2

Tinitial

3

Tfinal

4

ΔT

33

Multiple Choice

What variable is the goal?

An aqueous reaction releases 2000 J of energy into 53 grams of water at 22°C. What is the final temperature?

Assume the specific heat of solution is 4.18 J/g°C.

1

Q

2

Tinitial

3

Tfinal

4

ΔT

34

Multiple Choice

Select the derived equation to solve for the goal?

An aqueous reaction releases 2000 J of energy into 53 grams of water at 22°C. What is the final temperature?

Assume the specific heat of solution is 4.18 J/g°C.

1

Tf=Qmc+TiT_f=\frac{Q}{mc}+T_i

2

Tf=QmcTiT_f=\frac{Q}{mc}-T_i

3

Tf=QmcTiT_f=\frac{Q}{mc-T_i}

4

Tf=Qmc+TiT_f=\frac{Q}{mc+T_i}

35

Multiple Choice

Solve:

An aqueous reaction releases 2000 J of energy into 53 grams of water at 22°C. What is the final temperature?

Assume the specific heat of solution is 4.18 J/g°C.

1

22°C

2

31°C

3

9°C

4

13°C

5

49°C

36

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