AP CHEM Unit 3 Day 5 Review

AP CHEM Unit 3 Day 5 Review

11th Grade - University

22 Qs

quiz-placeholder

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AP CHEM Unit 3 Day 5 Review

AP CHEM Unit 3 Day 5 Review

Assessment

Quiz

Chemistry

11th Grade - University

Medium

NGSS
HS-PS1-2, HS-PS1-7, HS-PS2-4

+3

Standards-aligned

Created by

Patrick Boylan

Used 147+ times

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22 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the average current generated in the
Cu(s) + Fe3+(aq) → Cu2+(aq)+ Fe(s)
electrochemical cell if 50.0 g of Cu(s) are used up in a 24 hour period?
Cu2+ + 2 e → Cu Ered = +0.22 V
Fe3+ + 3 e → Fe Ered = −0.04 V

2.64 amp 
42.17 amp 
1.76 amp
13.00 amp

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

The reaction
2 Ag+(aq) + Fe(s) → Fe2+(aq) + 2 Ag(s)
taking place in a battery generates a current of 2 amp.
How much Fe(s) is consumed in 1 hour? 

4.16 g 
8.32 g
 1.04 g 
2.08 g

Tags

NGSS.HS-PS1-7

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

How long would a current of 10 mA take to produce 0.096000 g of Mo(s) from Mo5+(aq)?
Be careful with units!

48,243,000 s
48,243 s
9, 648.5 s 
9, 648, 500 s

Tags

NGSS.HS-PS1-7

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

A steel surface has been electroplated with 1.02g of vanadium (V, molar mass = 51 g/mol). If 9.65×103 C of charge were used, what was the original oxidation number of V?

+2
+3 
+4
+5

Tags

NGSS.HS-PS1-1

NGSS.HS-PS1-2

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

The (ampere, coulomb, volt, joule) is a quantity of electric charge and the (watt, ampere, faraday, volt) is the rate at which that charge flows.

joule; faraday 
ampere, volt
coulomb; ampere
volt; ampere 

Tags

NGSS.HS-PS2-4

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

If 6.6 moles of copper metal was deposited from a solution of Cu(NO3)2, how many electrons were involved? 

8.0 × 1024 electrons
6.0 × 1023 electrons
4.0 × 1024 electrons
2.0 × 1024 electrons

Tags

NGSS.HS-PS1-2

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

How many moles of of metallic iron (Fe) could be produced from Fe2+ at a current of 0.004amperes for 964,853 seconds?

0.02 mol Fe
0.2 mol Fe 
0.04 mol Fe 
0.4 mol Fe

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