Unit 5.3 Solving Quadratics EOC Review

Convert x²-6x+9 to factored form and identify the solution.

• (x-3)(x-3); x=3
• (x+3)(x+3); x=-3
• (x+4)(x+2); x=-4, -2
• Not factorable

Solve using square roots.

• A 
• B 
• C 
• D 

Solve x² - 9x + 8 = 0by factoring.

• x = 8 and 1
• x = -8 and 1
• x = 8 and -1
• x = -8 and -1

Solve using square roots.

• A
• B
• C
• D

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Solve using the quadratic formula.

• A
• B
• C
• D

Solve using the quadratic formula.

• A
• B
• C
• D

Solve using the quadratic formula.

• A
• B
• C
• D

What are the factors for a quadratic with zeros at x=-3 and x=3/4?

• (x-3/4)(x-3)
• (4x-3)(x+3)
• (x+3/4)(x-3)
• (4x+3/4)(x+3)

Convert x²-9x+20 to factored form and solve.

• (x-10)(x+2); x=-2, 10
• (x+4)(x+5); x=-5, -4
• (x-4)(x-5); x=4, 5
• Not factorable