Hess' Law

Hess' Law

12th Grade - University

8 Qs

quiz-placeholder

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Hess' Law

Hess' Law

Assessment

Quiz

Chemistry

12th Grade - University

Hard

NGSS
HS-PS1-4, HS-PS3-1

Standards-aligned

Used 244+ times

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8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The enthalpy change for the reaction
C(s, graphite) + 1⁄2O
2(g) --> CO(g)
cannot be measured directly since some carbon dioxide is always formed in the reaction.
It can be calculated using Hess’s Law and the enthalpy changes of combustion of graphite and of carbon monoxide.
C(s, graphite) + O2(g) --> CO2    ΔH=-394 kJmol–1
CO(g) + 1⁄2O2(g) --> CO2  
ΔH=-283 kJmol–1  
The enthalpy change for the reaction of graphite with oxygen to give carbon monoxide is 

-677 kJmol–1 
+111 kJmol–1 
-111 kJmol–1 
+677 kJmol–1 

Tags

NGSS.HS-PS1-4

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

The enthalpy change for the reaction, ∆Hr , is equal to 

∆H1 + ∆H2
∆H- ∆H2
-∆H1 - ∆H2
-∆H+ ∆H2

Tags

NGSS.HS-PS1-4

NGSS.HS-PS3-1

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The enthalpies of combustion of C(s), H2(g) and C4H9OH(l) (in kJmol-1) are as follows  
C(s) + O
2(g)   ->  CO2(g)  
                                             ∆H=a
H2(g) + ½O2(g)   ->   H2O(l)                                        ∆H=b
C4H9OH(l) + 6O2(g)   ->   4CO2(g) + 5H2O(l)  ∆H=c
What is the enthalpy change for the reaction shown below?
  4C(g) + 5H2(l) + ½O2(g)   ->   C4H9OH(l)

c – 4a – 5b
2a + 10b - c
4a + 5b - c
2a + 5b + c

Tags

NGSS.HS-PS1-4

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

The standard enthalpy changes of combustion of carbon, hydrogen and methane are shown in the table. 
Which one of the following expressions gives the correct value for the standard enthalpy change of formation of methane in kJ mol–1?
C(s) + 2H2(g) → CH4(g) 

394 + (2 × 286) – 891 
–394 – (2 × 286) + 891 
394 + 286 – 891 
–394 – 286 + 891 

Tags

NGSS.HS-PS1-4

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given the following data: ΔHf[FeO(s)] = –270kJmol–1
ΔHf [Fe2O3(s)] = –820 kJ mol–1
S
elect the expression which gives the enthalpy change, in kJ mol–1, for the reaction:
2FeO(s) + 1⁄2O2(g) → Fe2O3(s) 

(–820 × 1⁄2) + 270 = –140
(+820 × 1⁄2) – 270 = +140
–820 + (270 × 2) = –280 
+820 – (270 × 2) = +280 

Tags

NGSS.HS-PS1-4

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The standard enthalpy changes of formation of iron(II) oxide, FeO(s), and aluminium oxide, Al2O3(s), are –266 kJ mol–1 and –1676 kJ mol–1 respectively.
What is the enthalpy change under standard conditions for the following reaction?
3FeO(s) + 2Al (s)   ->   3Fe(s) + Al2O3(s) 

+878kJ 
–878kJ 
–1942kJ 
–2474kJ 

Tags

NGSS.HS-PS1-4

NGSS.HS-PS3-1

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Use the chart to answer the following question.
Which is correct about energy changes during bond breaking and bond formation? 

A
B
C
D

Tags

NGSS.HS-PS1-4

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