Solving Quadratics

• ±81
• ±9
• ±3
• No real solution

• -2, 4
• -8
• ±8
• No real solution

Tags

CCSS.HSA-REI.B.4B

• -2, 4
• -8
• ±8
• No real solution

• -4, 2
• -2, 4
• -16
• -4

Tags

CCSS.HSA-REI.B.4B

• -4, 2
• -2, 4
• -16
• -4

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property
• Yes, she factored correctly and then square rooted.
• No, she did factor correctly, but she can't use the zero product property as shown.
• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

9k² = 225

• 4
• 4, -4
• 25, -25
• -5, 5

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Solve the quadratic equation by factoring
a² + 10a + 21 = 0

• ± √21
• -3 , -7
• 3 , 7
• 28 , -7

Tags

CCSS.HSA-REI.B.4B