Factoring & Solving Polynomials

Factor:
x² + 7x - 30

• (x + 10)(x - 7)
• (x - 10)(x + 3)
• (x + 10)(x + 3)
• (x + 10)(x - 3)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:
x² - 49

• (x + 7)(x - 7)
• (x + 7)²
• (x - 7)²
• (x+7)(x-1)

Tags

CCSS.HSA.APR.C.4

Factor
5x²-28x+32

• (3x-10)(x+6)
• (x-8)(5x-4)
• (5x-8)(x-4)
• (5x-8)(x+7)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor: 8x³ - 1

• (2x - 1)(4x² + 2x + 1)
• (2x + 1)(4x² - 2x + 1)
• (2x - 1)(4x² - 2x - 1)
• (2x + 1)(4x² +2x + 1)

Tags

CCSS.HSA.APR.C.4

Factor: 16x⁴ - 25y⁶

• (4x² - 5y³)(4x² + 5y³)
• (16x²-15)(16x²+15)
• (4x-5)(16x²+20x+25)
• (4x-5y)(4x+5y)

Tags

CCSS.HSA.APR.C.4

Factor:
216x³+125

• 6(x+5)³
• (6x+5)³
• (6x+5)(6x²-30x+25)
• (6x+5)(36x²-30x+25)

Tags

CCSS.HSA.APR.C.4

Factor:
5n³ - 10n² + 3n - 6

• (5n²+3)(n-2)
• (5n²-3)(n-2)
• (5n³+3)(n-2)
• 10n(n²-6)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.APR.B.2

CCSS.HSA.SSE.A.2

Factor:
a⁵b - 64 ab

• ab(a⁴ - 64)
• ab(a² - 8)(a² + 8)
• ab(a - 4)(a² + 4a  + 16)
• ab(a - 2)²(a + 2)²

Tags

CCSS.HSA.APR.C.4

If p(x) = 9x⁴- 45x³ + 37x² + x +2, use synthetic substitution to find p(2).

• p(2) = 656
• p(2) = 652
• p(2) = -64
• p(2) = -368

Tags

CCSS.HSF.IF.A.2

How many zeros do you expect the polynomial function
 P(x) = 3x³+4x-8 to have?

• 1
• 2
• 3
• 4

Tags

CCSS.HSA.APR.B.3