Solving Quadratics

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property
• Yes, she factored correctly and then square rooted.
• No, she did factor correctly, but she can't use the zero product property as shown.
• No, she didn't factor correctly so the rest of her work is wrong. 

9k² = 225

• 4
• 4, -4
• 25, -25
• -5, 5

Solve the quadratic equation by factoring
a² + 10a + 21 = 0

• ± √21
• -3 , -7
• 3 , 7
• 28 , -7

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

In the equation
 (x + 2)(x - 3) = 0, the binomials are called...?

• Factors
• Products
• Multiples
• Zeros

Factor x²-16

• (x+4)²
• (x-4)²
• (x-16)(x+16)
• (x-4)(x+4)

Which of the following equations matches standard form of a quadratic?

• ax + by = c
• y = a(x - h)² + k
• y = ax² + bx + c
• y = mx + b

Tags

CCSS.HSA.SSE.B.3

Solve by factoring  7x²  - 28x = 0

• x = 4, x = 7
• x = 0, x  = 4
• x = 0, x = -4
• x = -4, x = -7

Where are the roots for this parabola:
y = 2x² - 3x - 5

• (-1,0) and (2.5,0)
• there are none
• (1,0) and (-2.5,0) 
• (2,0) and (-3,0)

Solve by completing the square.
k² − 12k + 23 = 0

• {6 + √13, 6 - √13}
• {-6 + √13, -6 - √13}
• {6 + √59, 6 - √59}
• {-6 + √59, -6 - √59}