Algebra 2 Review for Final Exam

What is the equation of this graph?

• f(x) = (x -5)² + 1
• f(x) = (x - 1)² - 5
• f(x) = (x + 1)² - 5
• f(x) = (x + 5)² +1

Tags

CCSS.HSF-IF.C.7A

Use the graph to determine the solutions.
*Hint: Solutions = roots = zeros = x-intercepts

• -1 and -3
• 1 and -3
• 1 and 3
• -1 and 3

What is the equation for axis of symmetry?

• y=3
• x=3
• x=5
• x=1

What is the vertex?

• (2, 4)
• (3, -1)
• (0, 8)
• (4, 2)

Tags

CCSS.HSF-IF.C.7A

Find the x-intercepts of the equation f(x)=x²+2x-24

• (4,0)  (-6,0)
• (0,-24)
• (6,0)  (-4,0)
• (5,0)  (0,0)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Find the y-intercept of f(x) = 2x² - 2x + 1

• 2
• -2
• 1
• -1

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

CCSS.HSA.REI.B.4

Solve x² - 5x + 10 = 0

• (5 - i√15)/2  ,  (5 + i√15)/2
• (5 - √15)/2  ,  (5 + √15)/2
• (5 - i√65)/2  ,  (5 + i√65)/2
• (5 - √65)/2  ,  (5 + √65)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Evaluate (9 + 3i) (9 - 3i). 

• 81 -9i
• 90
• 81 + 27i -9i²
• 81i - 9

Tags

CCSS.HSA.APR.A.1

(10+3i) - (2-9i)

• 20-27i
• 12-7i
• 8+12i
• 20-27i²

Tags

CCSS.HSA.APR.A.1

The height of an object thrown into the air can be modeled by the formula h(t) = -16t² + 70t + 95, where h(t) is in feet after t seconds.
What is the height of the object after 5 seconds?

• 95 feet
• 45 feet
• 70 feet
• 171.56 feet

Tags

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

CCSS.HSA.SSE.A.1