Solve for n: 40 − 3 n = 61 40-3n=61 4 0 − 3 n = 6 1

n = − 101 3 n=-\frac{101}{3} n = − 3 1 0 1

n = 101 3 n=\frac{101}{3} n = 3 1 0 1

Solve for c: 10 c − 6 = − 3 ( − 4 c + 2 ) + 4 c + 5 10c-6=-3\left(-4c+2\right)+4c+5 1 0 c − 6 = − 3 ( − 4 c + 2 ) + 4 c + 5

c = − 5 6 c=-\frac{5}{6} c = − 6 5

c = − 26 5 c=-\frac{26}{5} c = − 5 2 6

Solve for p: 3 ( 4 3 p + 5 3 ) = − 4 ( − 7 p + 7 ) 3\left(\frac{4}{3}p+\frac{5}{3}\right)=-4\left(-7p+7\right) 3 ( 3 4 p + 3 5 ) = − 4 ( − 7 p + 7 )

p = 11 8 p=\frac{11}{8} p = 8 1 1

p = 23 24 p=\frac{23}{24} p = 2 4 2 3

Solve the inequality: 4 ≤ x + 8 4\le x+8 4 ≤ x + 8

x ≥ − 12 x\ge-12 x ≥ − 1 2

Joey Chestnut is trying to break his own world record for eating the most hot dogs and buns in 10 minutes. He needs to eat more than 72 hot dogs to break his record. After 1 minute of competition, Joey has eaten 10 hot dogs. Joey wants to know the number of hot dogs per minute that he needs to eat for the next 9 minutes to break his own record. Let d represent the number of hot dogs Joey eats per minute. Which inequality shows the number of hot dogs per minute Joey must eat for the last 9 minutes to break his record?

9 d + 10 > 72 9d+10>72 9 d + 1 0 > 7 2

9 d + 10 < 72 9d+10<72 9 d + 1 0 < 7 2

9 d − 10 > 72 9d-10>72 9 d − 1 0 > 7 2

9 d − 10 < 72 9d-10<72 9 d − 1 0 < 7 2

Sally uses a 30% off coupon to buy a video game at Game Stop. Which expression DOES NOT represent the discounted final price Sally would have to pay for the video game that normally costs "g" dollars?

g − 0.3 g g-0.3g g − 0 . 3 g

Simplify: − 10 m − 6 d + 15 d − ( − 8 m ) -10m-6d+15d-\left(-8m\right) − 1 0 m − 6 d + 1 5 d − ( − 8 m )

− 2 m + 9 d -2m+9d − 2 m + 9 d

− 2 d + 9 m -2d+9m − 2 d + 9 m

Solve for g: − 11 2 = g − 2 + 1 4 -\frac{11}{2}=\frac{g}{-2}+\frac{1}{4} − 2 1 1 = − 2 g + 4 1

g = 23 2 g=\frac{23}{2} g = 2 2 3

g = 11 2 g=\frac{11}{2} g = 2 1 1

g = 7 12 g=\frac{7}{12} g = 1 2 7

Taxi company A charges $8.00 to get into the cab and $0.75 per mile. Taxi company B charges $6.00 to get into a cab and $1.25 per mile. Which equation can be used to determine the number of miles (m) where the cost of the ride would be the same for both companies?

8 + 0.75 m = 6 + 1.25 m 8+0.75m=6+1.25m 8 + 0 . 7 5 m = 6 + 1 . 2 5 m

8 − 0.75 m = 6 − 1.25 m 8-0.75m=6-1.25m 8 − 0 . 7 5 m = 6 − 1 . 2 5 m

8 m + 0.75 = 6 m + 1.25 8m+0.75=6m+1.25 8 m + 0 . 7 5 = 6 m + 1 . 2 5

8 m − 0.75 = 6 m − 1.25 8m-0.75=6m-1.25 8 m − 0 . 7 5 = 6 m − 1 . 2 5

Expressions, Equations, Inequalities Test Review (Pre-Alg)

7th - 8th Grade

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Expressions, Equations, Inequalities Test Review (Pre-Alg)

Quiz

•

Mathematics

•

7th - 8th Grade

•

Practice Problem

•

Medium

•

CCSS

HSA.REI.B.3, 7.EE.B.4B, 7.EE.B.4A

Standards-aligned

Suzanne DeValue

Used 24+ times

FREE Resource

20 questions

Show all answers

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Both

Neither

Tags

CCSS.6.EE.A.4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tags

CCSS.7.EE.B.4A

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tags

CCSS.6.EE.B.7

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve for n:
$40-3n=61$

$n=-\frac{101}{3}$

$n=\frac{101}{3}$

$n=7$

$n=-7$

Tags

CCSS.7.EE.B.4A

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tags

CCSS.8.EE.C.7B

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

No Solution

All Real Numbers

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve for c:

$10c-6=-3\left(-4c+2\right)+4c+5$

$c=-\frac{5}{6}$

$c=-\frac{26}{5}$

No Solution

All Real Numbers

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

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Expressions, Equations, Inequalities Test Review (Pre-Alg)

20 questions

Solve for n:
$40-3n=61$

Solve for c:

$10c-6=-3\left(-4c+2\right)+4c+5$

Solve for p:

$3\left(\frac{4}{3}p+\frac{5}{3}\right)=-4\left(-7p+7\right)$

Solve the inequality:

$4\le x+8$

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Expressions, Equations, Inequalities Test Review (Pre-Alg)

20 questions

Solve for n: 40−3n=6140-3n=6140−3n=61

Solve for c: 10c−6=−3(−4c+2)+4c+510c-6=-3\left(-4c+2\right)+4c+510c−6=−3(−4c+2)+4c+5

Solve for p: 3(43p+53)=−4(−7p+7)3\left(\frac{4}{3}p+\frac{5}{3}\right)=-4\left(-7p+7\right)3(34​p+35​)=−4(−7p+7)

Solve the inequality: 4≤x+84\le x+84≤x+8

Create a free account and access millions of resources

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Popular Resources on Wayground

Discover more resources for Mathematics

Solve for n:
$40-3n=61$

Solve for c:

$10c-6=-3\left(-4c+2\right)+4c+5$

Solve for p:

$3\left(\frac{4}{3}p+\frac{5}{3}\right)=-4\left(-7p+7\right)$

Solve the inequality:

$4\le x+8$