Solving by factoring

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5
• x = 20 and x = -9
• x = 4 and x = 5
• x = -4 and x = 5

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6
• x = 3 and x = -6
• x = -9 and x = 2
• x = 9 and x = -2

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: 5x² + 13x + 6 = 0

• x = -2 and x = -3/5
• x = 2 and x = 3/5
• x = -2 and x = 3/5
• x = 2 and x = -3/5

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: 2x² - 5x - 12 = 0

• x = -4 and x = -6
• x = 4 and x = -3/2
• x = 4 and x = 6
• x = -4 and x = 3/2

Tags

CCSS.HSA-REI.B.4B

Factor:   3x²- 6x - 24

• (3x - 8)(x + 3)
• (3x + 4)(x - 6)
• 3(x - 2)(x + 4)
• 3(x + 2)(x - 4)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

7x² - 26x - 8 = 0

• x = -1 and x = -7/8
• x = 4 and x = -2/7
• x = -4 and x = 2/7
• x = 4 and x = -7/2

Tags

CCSS.HSA-REI.B.4B

Factor Completely:

x² - 36

• (x + 9)(x - 4)

• (x - 6)(x - 6)

• (x - 9)(x + 4)

• (x + 6)(x - 6)

Tags

CCSS.HSA.APR.C.4

In the equation
 (x + 2)(x - 3) = 0, the binomials are called...?

• Factors
• Products
• Multiples
• Zeros

Tags

CCSS.HSA.APR.B.2

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B