7.5 Solving Logarithms

Solve:
_{log (4x − 5) = log (2x − 1)} 

• 0
• 1
• 2
• 3

log (2x - 2) = log 5

• 7

• 7/2

• 3/2

• 2/3

log₂(x + 3) = 5

• x=2

• x=29

• x=7

• x=32

Rewrite the equation in exponential form:
log_x81 = 4

• x⁴ = 81
• 4^x = 81
• 81^x = 4
• 81⁴ = x

Tags

CCSS.HSF.BF.B.5

Solve for x:
2^{3x + 1} = 32

• 0
• -1
• 5/3
• 4/3

Solve for x:
4^x- 5 = 12

• 0.489
• 2.552
• 0.893
• 2.044

Tags

CCSS.7.EE.B.4A

log₃(5x + 2) = 3

• 5

• 1/5

• 1

• 5/3

4^x+3 - 5 = 11

• 13

• 5

• -1

• 3

Tags

CCSS.7.EE.B.4A

log₂(x + 5) = 3

• 3
• 4
• 5
• 6