Mole/Mole and Mole/Mass Problems

This is the equation for the catalytic oxidation of ammonia.

4NH₃ + 5O₂ --> 4NO + 6H₂O. How many moles of NO are formed if 824 g of NH₃ react?

• 4 moles

• 48.5 moles

• 97 moles

• 824 g

This is the equation for the catalytic oxidation of ammonia.

4NH₃ + 5O₂ --> 4NO + 6H₂O. How many grams of water are formed if 2.5 moles of ammonia are oxidized?

• .093 g

• 2 moles

• .092592592 moles

• 5

This is the equation for the catalytic oxidation of ammonia.

4NH₃ + 5O₂ --> 4NO + 6H₂O. How many moles of oxygen are needed to react with 4.6 moles of ammonia?

• 20 g

• 5 moles

• 5.8 moles

• 11.6 moles

Mercury (II) oxide decomposes into mercury and oxygen gas according to the following balanced equation:

2HgO --> 2Hg + O₂

How many moles of mercury (II) oxide are needed to produce 125 g of oxygen?

• 7.81 moles

• 8 g

• 14 moles

• 250 g

Mercury (II) oxide decomposes into mercury and oxygen gas according to the following balanced equation:

2HgO --> 2Hg + O₂

How many grams of oxygen will be produced if 2.3 moles of mercury are produced?

• 52 g

• 98.5 g

• 4 moles

• 37 g

Mercury (II) oxide decomposes into mercury and oxygen gas according to the following balanced equation:

2HgO --> 2Hg + O_2.

How many moles of mercury are produced if 24.5 moles of mercury (II) oxide decompose?

• 2 moles

• 24.5 moles

• 1 mole

• 12.25 moles