Converting Vertex and standard forms of quadratics/Solve
Authored by Alex Houser
Mathematics
9th - 11th Grade
CCSS covered
Used 29+ times
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15 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Convert
f(x) = 3(x - 5)2 - 1
to standard form.
f(x) = 3x2 -30x + 74
f(x) = 3x2 -10x + 24
f(x) = 3x2 -30x + 24
f(x) = 3x2 -30x + 75
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Convert
f(x) = 2(x - 2)2 +9
to standard form.
f(x) = 2x2 + 8x + 9
f(x) = 2x2 - 8x - 4
f(x) = 2x2 - 8x + 17
f(x) = 2x2 - 8x + 8
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Convert
f(x) = -4(x - 1)2 +7
to standard form.
f(x) = -4x2 + 3
f(x) = -4x2 - 8x + 17
f(x) = -4x2 +8x - 11
f(x) = -4x2 +8x + 3
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Convert to vertex form.
y=-(x-5)2 + 21
y=-(x+5)2 + 21
y=-(x+10)2 + 21
y=-(x-10)2 + 21
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
If given the equation y = 3(x + 5)2 - 4, what is the vertex of the parabola?
(5, -4)
(-5, -4)
(-15, -4)
(15, -4)
Tags
CCSS.HSF.IF.B.4
CCSS.HSF.IF.C.7
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Convert the equation y= x2-2x-5 into vertex form.
y= (x-1)2-6
y= -(x-1)2-6
y= (x+1)2-6
y= -(x+6)2-1
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
x2-2x-5
(x-1)2-6
(x+1)2+6
(x+1)2-7
(x-1)2+7
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