Confidence Intervals for Proportions REVIEW

Quiz
•
Mathematics
•
11th - 12th Grade
•
Medium
Standards-aligned
Nichole Nelmark
Used 25+ times
FREE Resource
20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Given: p = 0.30, n = 36. Calculate: 90% confidence interval
(0.175, 0.425)
(0.155, 0.456)
(0.108, 0.503)
(0.202, 0.398)
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: p = 0.08, n = 100. Calculate: 99% confidence interval
(0.027, 0.133)
(0.0354, 0.125)
(0.010, 0.150)
(0.041, 0.119)
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given: p = 0.38, n = 81. Calculate: 95% confidence interval
(0.274, 0.486)
(0.205, 0.560)
(0.244, 0.522)
(0.294, 0.472)
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A study found that in a sample of 44 subjects, 9 of agree that children under 6 shouldn’t be taken to nice restaurants. Calculate a 95% confidence interval for p.
(0.105, 0.305)
(0.082, 0.318)
(0.117, 0.292)
(0.048, 0.361)
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A study found that in a sample of 44 subjects, 9 of agree that children under 6 shouldn’t be taken to nice restaurants.
The 95% confidence interval for p is (0.082, 0.318). Interpret this interval.
95% of the time the proportion of people who believe children under 6 shouldn't be taken to nice restaurants will be between 8.2% and 31.8%.
The population proportion of people who believe children under 6 shouldn't be taken to nice restaurants is between 8.2% and 31.8%.
The probability that the proportion of people who believe children under 6 shouldn't be taken to nice restaurants will be between 8.2% and 31.8% is 95%.
Based on this sample, I am 95% confident that the proportion of people who believe children under 6 shouldn't be taken to nice restaurants is between 8.2% and 31.8%.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A survey of 121 subjects found that 84 have suffered the symptoms of depression in the last year. Calculate a 90% confidence interval for p.
(0.612, 0.776)
(0.641, 0.748)
(0.780, 0.900)
(0.621, 0.759)
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A survey of 121 subjects found that 84 have suffered the symptoms of depression in the last year.
A 90% confidence interval for p is (0.621, 0.759). Interpret this interval.
Based on this sample, I am 90% confident that the true proportion of people who have suffered the symptoms of depression in the last year is between 62.1% and 75.9%.
90% of the time, the population of people who have suffered the symptoms of depression in the last year is between 62.1% and 75.9%
90% of all of the possible intervals calculated using this method will capture the true proportion of people who have suffered the symptoms of depression in the last year.
The probability that people who have suffered the symptoms of depression in the last year is between 62.1% and 75.9% is 90%.
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