Ch 4 Test Review Logs/Exp College Algebra

Solve:
_{log (4x − 5) = log (2x − 1)} 

• 0
• 1
• 2
• 3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Solve the following equation.  Round your solution to two decimal places.
4 - 3 ln(2x + 10) = 12

• x = 2.20
• x = 1.68
• x = -5.00
• x = -4.97

Tags

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

log₂(x + 5) = 3

• 3
• 4
• 5
• 6

Tags

CCSS.HSF.BF.B.5

log x = -3

• x=10
• x=.001
• x=3
  x=.01
• 3

Tags

CCSS.HSF.BF.B.5

ln(4-v) = ln(3v)

• 1
• -2
• No Solution
• -5

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.A.2

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

LT 7 - 10: I can evaluate values of e and use natural logarithms.
Solve the following equation.  Round your answer to two decimal places;
5 ln(x) = 7

• x = 4.06
• x = 2.04
• No solution
• None of the above

Tags

CCSS.HSF.BF.B.5

LT 7 - 7: I can solve a logarithm by rewriting as an exponential.
Solve for x given 4log₃(x-5)=12

• 7,144,934
• 27
• 437
• 32

Write in exponential form.
log₂(¹/₈) = -3

• 2^-3 = ¹/₈
• 2^1/8 = -3
• -3² = ¹/₈
• -3^1/8 = 2

Tags

CCSS.HSF.BF.B.5

Expand the logarithm.

• A
• B
• C
• D

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

Rewrite the equation in logarithmic form.

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5