Solving Quadratics by Factoring

Factor:
x² + 5x - 24

• (x - 8)(x + 3)
• (x + 8)(x - 3)
• (x + 6)(x - 4)
• (x + 12)(x - 2)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:

x² + 11x + 24

• (x + 6)(x + 4)

• (x + 12)(x + 2)

• (x - 8)(x - 3)

• (x + 8)(x + 3)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:
x² - 10x + 24

• (x - 6)(x - 4)
• (x + 6)(x + 4)
• (x - 12)(x + 2)
• (x - 8)(x - 3)

Tags

CCSS.7.EE.A.1

Factor:
x² - 10x - 24

• (x + 12)(x - 2)
• (x - 6)(x - 4)
• (x - 12)(x + 2)
• (x +6)(x - 4)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:
x² - 14x + 24

• (x - 8)(x - 3)
• (x - 12)(x - 2)
• (x - 6)(x - 4)
• (x - 24)(x - 1)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5
• x = 20 and x = -9
• x = 4 and x = 5
• x = -4 and x = 5

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6
• x = 3 and x = -6
• x = -9 and x = 2
• x = 9 and x = -2

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Solve
a² + 2a - 24 = 0

• a = -6, 4
• a = 6, -4
• a = 12, -2
• a = 8, -3

Tags

CCSS.HSA-REI.B.4B

x²+4x-32=0

• x= -8, 4

• x= 8, -4

• x= -8, -4

Tags

CCSS.HSA-REI.B.4B