Natural Log & Exponential Growth and Decay

Solve the following equation for x.  Round your solution to two decimal places.
ln3x + ln2x = 3

• x = 12.91
• x = 4.02
• x = 3.35
• x = 1.83

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.4

CCSS.HSA.REI.A.1

What is the value of ln(e⁷)

• 2.718...
• 1
• 7
• Does not exist

Tags

CCSS.HSF.BF.B.5

Solve 5e^{3x - 2} + 15 = 35

• 1.13
• 1.29
• 1.10
• 0.87

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.4

CCSS.HSA.REI.A.1

Rewrite in exponential form:
ln(2) = x

• 2^x = 10
• 10² = x
• e^x = 2
• e² = x

Tags

CCSS.HSF.BF.B.5

Which of the following is the value of x given;
e^(x+6) = 12

• x = ln 6
• x = -6 + ln12
• x = ln72
• x = ln(-2)

Tags

CCSS.HSF.BF.B.5

Solve for x:

ln(x)=2

• 2.234

• 3.14

• 7.389

• 2

Tags

CCSS.HSF.BF.B.5

If $1,000 is invested at 16% interest, compounded continuously, for five years, what is the ending balance?

• $1,225,54
• $2,225.54
• $22,255.40
• $225.54

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.A.1

CCSS.HSF.BF.A.1

CCSS.HSF.LE.B.5

Expand ln xy²z³

• 6(lnx + lny - lnz)
• lnx + 2lny - 3lnz
• lnx + (1/2)lny + (1/3)lnz
• lnx + 2lny + 3lnz

Tags

CCSS.HSF.BF.B.5

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.IF.C.8

Which of the following functions shows an initial amount of $15 and an increase of 35% each year?

• y = 15(35)^x
• y = 15(1.35)^x
• y = 15(0.35)^x
• y = 35(1.15)^x

Tags

CCSS.HSF.LE.A.2

Classify the model as Exponential GROWTH or DECAY.
A=1200(.85)⁶

• Growth
• Decay

Tags

CCSS.HSF-IF.C.8B