In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

In the equation (x-4)²+(x-3)²=25, the center of the circle is at...

• (-3, -4)
• (4, 3)
• (-4, -3)
• (3, 4)

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=3
• x²+y²=6
• x²+y²=9

Tags

CCSS.HSG.GPE.A.1

Which graph corresponds to 
(x)²+ (y-6)²=9

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

Which graph corresponds to

(x-4)²+ (y+4)²=25

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1

Which graph corresponds to

(x+2)²+ (y-3)²=36

• A

• B

• C

• D

Tags

CCSS.HSG.GPE.A.1

In order to convert from general form to center-radius form, you must ___________. 

• Multiply out
• expand
• factor
• complete the square

Tags

CCSS.HSG.GPE.A.1

How can we find the general form of a circle? 

• divide out the center-radius form
• multiply out the center-radius form
• factor out the center-radius form
• add up the center-radius form

Tags

CCSS.HSG.GPE.A.1