Algebra 1 Math Camp Review

Which of the following equations could be used to solve:
y = x² + 3x - 5
y = x + 3

• x² - 3x + 5 = x - 3
• x² + 3x - 5 = x + 3
• x² + 3x - 5 + x + 3 = 0
• x² + 3x - 5 = 0

Tags

CCSS.HSA-REI.B.4B

Given the system 
y = x² + 3x - 5
y = x + 3
Write the substitution equation (x² + 3x - 5 = x + 3) in standard form.

• x² + 4x - 2 = 0
• x² - 2x + 8 = 0
• x² + 2x - 8 = 0
• x² + 4x - 8 = 0

Tags

CCSS.HSA.REI.C.7

Given the system of equations:
y = x² + 3x - 5
y = x + 3
When x = -4, what is the value of y?

• -1
• 1
• 7
• -33

Tags

CCSS.HSA.REI.C.7

Given the system of equations:
y = x² + 3x - 5
y = x + 3
When x = 2, what is the value of y?

• 6
• -1
• 5
• -5

Tags

CCSS.HSA.REI.C.7

What are the solutions to the system:
y = x² + 3x - 5
y = x + 3

• (-4, 2) and (-1, 5)
• (-4, -1) and (2, 5)
• (2, -1 and (-4, 5)
• (-4, 1) and (2, -1)

Tags

CCSS.HSA.REI.C.7

Find the solution:
y = x² - 4x + 6
y = x + 2

• (3, 1) and (6, 4)
• (-1, 1) and (4, 2)
• (1, 3) and (4, 6)
• (1, 4) and (3, 6)

Tags

CCSS.HSA.REI.C.7

Factor:
x² + 5x - 24

• (x - 8)(x + 3)
• (x + 8)(x - 3)
• (x + 6)(x - 4)
• (x + 12)(x - 2)

Factor
k² -2k - 24

• (k+4)(k-6)
• (k+4)(k+6)
• (k+6)(k-1)
• (k-4)(k+6)

Factor:
 3x²-17x+10

• (x-5)(3x-2)
• (x+5)(3x+2)
• (3x-5)(x-2)
• (x+5)(3x-2)

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:
 2x² - 7x + 6

• (x -1)(2x - 6)
• (x - 3) (2x - 2)
• (x - 2) (2x - 3)
• (x - 6) (2x - 1)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3