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Derivatives Chapter 3

Authored by Catherine Stevens

Mathematics

12th Grade - University

CCSS covered

Used 51+ times

Derivatives Chapter 3
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31 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find  dydx\frac{dy}{dx}  .    


 y=32x5+2x3−53x2y=\frac{3}{2}x^5+2x^3-\frac{5}{3}x^2  

 dydx=152x4+6x2−103x\frac{dy}{dx}=\frac{15}{2}x^4+6x^2-\frac{10}{3}x^{ }  

 dydx=152x2+6x3−103x\frac{dy}{dx}=\frac{15}{2}x^2+6x^3-\frac{10}{3}x^{ }  

 dydx=32x4+2x2−53x\frac{dy}{dx}=\frac{3}{2}x^4+2x^2-\frac{5}{3}x  

 dydx=152x+6x−103x\frac{dy}{dx}=\frac{15}{2}x+6x-\frac{10}{3}x^{ }  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find  dydx\frac{dy}{dx}  



 y=(3x2+3)(5x2+3)y=\left(3x^2+3\right)\left(5x^2+3\right)   


 dydx=60x3+48x\frac{dy}{dx}=60x^3+48x  

 dydx=30x3+18x\frac{dy}{dx}=30x^3+18x  

 dydx=3x2+6x+3\frac{dy}{dx}=3x^2+6x+3  

 dydx=15x4+84x2+9\frac{dy}{dx}=15x^4+84x^2+9  

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find  dydx\frac{dy}{dx}  . 

  y=5x2+44x2+5y=\frac{5x^2+4}{4x^2+5}  

 dydx=18x(4x2+5)2\frac{dy}{dx}=\frac{18x}{\left(4x^2+5\right)^2}  

 dydx=18x4x2+5\frac{dy}{dx}=\frac{18x}{4x^2+5}  

 dydx=40x3+32x(4x2+5)2\frac{dy}{dx}=\frac{40x^3+32x}{\left(4x^2+5\right)^2}  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find y'.

 y=5x2sec⁡xy=5x^2\sec x  


 y′=10xsec⁡x+5x2sec⁡xtan⁡xy'=10x\sec x+5x^2\sec x\tan x  

 y′=5xsec⁡2x+10xsec⁡xtan⁡xy'=5x\sec^2x+10x\sec x\tan x  

 y′=10xsec⁡xtan⁡xy'=10x\sec x\tan x  

 y′=5x2sec⁡x+10xsec⁡xtan⁡xy'=5x^2\sec x+10x\sec x\tan x  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 y=x2sin⁡x + cos⁡xy=x^2\sin x\ +\ \cos x  

Find y'.

 y′=(2x−1)sin⁡x+x2cos⁡xy'=\left(2x-1\right)\sin x+x^2\cos x  

 y′=xsin⁡x+cos⁡xy'=x\sin x+\cos x  

 y′=2xcos⁡x−sin⁡xy'=2x\cos x-\sin x  

 y′=2xsin⁡x+cos⁡x−x2sin⁡xy'=2x\sin x+\cos x-x^2\sin x  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Find the derivative.

 y=1x2y=\frac{1}{x^2}  

 y′=−2xy'=-2x  

 y′=−2x3y'=-\frac{2}{x^3}  

 y′=2xy'=2x  

 y′=x2y'=\frac{x}{2} 

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Find the derivative.


y = x4 tan x

y' = x4 sec2x - 4x3tanx

y' = x4 sec2x + 4x3tanx

y' = 4x3sec2x

y' = -4x3 tanx

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