Solving Systems by Substitution

Solve by substitution.

y = 2x + 1

y = 4x - 1

• (1,3)

• (-1,-3)

• (-1,3)

• (3,1)

What is the solution to the system of equations? 
y = 3x - 8
y = 4 - x

• (3,1)
• (1,3)
• (-3,1)
• (3,-1)

Solve the system of equations by substitution.
y = -4x + 5
y =  3x - 16

• (-3, -25)
• (3,-7)
• (11, 17)
• (21, 47)

Solve:
y=8x+1
y=6x+3

• (1, 9)
• (4, 14)
• (0, 1)
• (2, 4)

Solve:
y = -3x -4
y = -8x - 9

• (5, 5)
• (-5, -5)
• (11, 13)
• (-1 , -1)

y = 5x + 1
y = 3x + 13

• (6, 31)
• (31, 6)
• (4, 21)
• (2, 11)

Solve the system by substitution.

y = 3x + 1

y = x + 3

• (-4, 1)

• (4, 1)

• (1, 4)

• (-1, 4)

Solve this system of equations
y=8x-5
y=2x+19

• (1,3)
• (2.4, 23.8)
• (2.5,15)
• (4,27)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6