Zeros of a Polynomial

Factor:
x² + 5x - 24

• (x - 8)(x + 3)
• (x + 8)(x - 3)
• (x + 6)(x - 4)
• (x + 12)(x - 2)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:

x² + 11x + 24

• (x + 6)(x + 4)

• (x + 12)(x + 2)

• (x - 8)(x - 3)

• (x + 8)(x + 3)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:
5x³-7x²

• x²(5x-7)
• x(5x²-7x)
• x³(5-7x)
• Prime

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:
24c⁵ - 12c³

• 6(4c⁵ - 2c³)
• 12c³(2c²)
• 12c³(2c² - 1)
• 12c³(2c² - 0)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor:
18b²-9b³

• 9b²(18-9b)
• 9b²(2-b)
• 9b²(18-9b²)
• b²(2-b²)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

If your solution is x = 5, then your factor is

• (x + 5)

• 5x

• (x - 5)

• -5x

Tags

CCSS.HSA.APR.B.2

What is the standard form of a quadratic equation?

• y = mx + b

• y = x²

• ax + by = c

• ax² + bx + c = 0

How else can you say solution? Choose all that are correct!!

• root

• x-intercept

• factor

• zero

• GCF

Tags

CCSS.HSA-REI.B.4B

Factor the following: 2x² + x - 15

• (2x - 5)(x + 3)

• (2x + 5)(x - 3)

• (5x - 2)(x + 3)

• (5x + 2)(x - 3)

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Use Synthetic Substitution to find f(-2)
f(x) = 2x⁴ - 3x³ + 1

• A.  f(-2) = 51
• B.  f(-2) = 11
• C.  f(-2) = 63
• D.  f(-2) = 57