Geometry Semester 1 Review Part 1

Solve for x

• x = 2
• x = 4
• x = 6
• x = 8

Tags

CCSS.4.MD.A.2

• x=67
• x=43
• x=55
• x=12

Tags

CCSS.HSG.CO.C.9

• m∠GHK=80.5,

  m∠KHJ=161

• m∠GHK=161,

  m∠KHJ=80.5

• m∠GHK=80.5,

  m∠KHJ=80.5

• m∠GHK=161,

  m∠KHJ=161

Tags

CCSS.HSG.CO.C.9

Let B be between A and C.

• 28
• 4
• 16
• 12

Tags

CCSS.4.MD.A.2

What is the midpoint between (3, -1) and (7, -5)

• (5, -2)
• (10, -6)
• (5, -3)
• (2, -2)

Tags

CCSS.HSG.GPE.B.6

What is the midpoint between (-4,4) and (-2,2)?

• (3,2)
• (-3,3)
• (4,5)
• (6,7)

Tags

CCSS.HSG.GPE.B.6

Find the distance between (-4, 5)
and (7, 18).

• √202
• √538
• √178
• √290

Tags

CCSS.HSG.GPE.B.7

Find the distance between (-5, -8) and (-1, -16).

• 8.9
• 9.8
• 10.3
• 11

Tags

CCSS.HSG.GPE.B.7

Given, "If I have a Siberian Husky, then I have a dog." Identify the converse.

• If I do not have a Siberian Husky, then I do not have a dog.
• If I have a dog, then I have a Siberian Husky.
• If I do not have a dog, then I do not have a Siberian Husky.
• If I do not have a Siberian Husky, then I have a dog. 

Tags

CCSS.L.2.1F

CCSS.L.8.1C

CCSS.L.8.3A

Given, "If I have a Siberian Husky, then I have a dog." Identify the inverse.

• If I do not have a Siberian Husky, then I do not have a dog.
• If I have a dog, then I have a Siberian Husky.
• If I do not have a dog, then I do not have a Siberian Husky.
• If I do not have a Siberian Husky, then I have a dog. 

Tags

CCSS.L.2.1F

CCSS.L.8.1C

CCSS.L.8.3A